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Lynna [10]
2 years ago
14

2. What are the solutions to the quadratic equation

Mathematics
1 answer:
Svetlanka [38]2 years ago
8 0

Answer:

The answer is x=5 and x=−5

x² - 25 = 0

(x-5)(x+5)=0

x²-5x+5x-25=0

x-5=0 x+5=0

x=5 or x=-5

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Write (4p^4) ^2 without exponents.
Inessa [10]

Answer:

(4p * 4p * 4p * 4p) * (4p * 4p * 4p * 4p)

Step-by-step explanation:

exponent is the number being multiplied by itself a number of times

2^4 is 2*2*2*2

3^1 is 3

7 0
2 years ago
!! AP CALCULUS AB !!<br> find the limit of [(secx*sinx) + (cscx*cosx)]/(3secx) as x approaches 3pi/2
uysha [10]

f(x)= \frac{\frac{\sin{x}}{\cos{x}}+\frac{\cos{x}}{\sin{x}}}{3\sec{x}}

\frac{\frac{\sin{x}}{\cos{x}}+\frac{\cos{x}}{\sin{x}}}{3\sec{x}} \implies \\ \frac{\sin^2{x}+\cos^2{x}}{\sin{x}\cos{x}}\frac{\cos{x}}{3}\implies \\\frac{1}{\sin{x}\cos{x}}*\frac{\cos{x}}{3}\implies \\ \frac{1}{3\sin{x}}

So,

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6 0
3 years ago
What is the value of 14-a^{2} given a=-3?
BlackZzzverrR [31]

Answer:

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8 0
2 years ago
Which of the following is the best estimate of 12 18/21?
lions [1.4K]

Answer:

Your simplified fraction would be 12 6/7 so I’d say *C* because that’s the closest to the simplified fraction

Step-by-step explanation:

im  just explain

8 0
3 years ago
Read 2 more answers
The product of two consecutive numbers exceeds the square
Lyrx [107]

Answer:

20,21

Step-by-step explanation:

Let x be the first number.

Let y be the 2nd number.

Given y - x = 1 (since they are consecutive)

Rearrange it: y = x+1 (equation 1)

Also given:

xy-20=x^{2} (equation 2)

Now we can substitute y = x + 1 into equation 2.

x(x+1)-20 = x^{2} \\x^{2} +x-20 = x^{2} \\x-20=x^{2} -x^{2} \\x-20=0\\x=20

Since we know x, the smaller number is 20, we can substitute to equation 1 to find y, the larger number.

y = 20+1

= 21.

Therefore the 2 numbers are 20 and 21.

8 0
1 year ago
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