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kicyunya [14]
2 years ago
6

If each side of a triangle measures 0.75 inches, what is the perimeter of the triangle?

Mathematics
2 answers:
Goryan [66]2 years ago
7 0

Answer:

.75*3

Step-by-step explanation:

you can multiply or add .75 5hree times, it dont matter which. the perimeter of the triangle is 2.25

mestny [16]2 years ago
3 0

Answer:

0.75+0.75+0.75=2.25 inches

triangles are equal.So add 0.75 three times and write the answer as I mentioned. Also you must do it according to the book.I mean like,you adds it 3 times because triangle is 3 sided and it's a equilateral triangle.

Are you in Grade 8? bcoz me too.

btw I hope this helps you..

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For the given term, find the binomial raised to the power, whose expansion it came from: 15(5)^2 (-1/2 x) ^4
Elina [12.6K]

Answer:

<em>C.</em> (5-\frac{1}{2})^6

Step-by-step explanation:

Given

15(5)^2(-\frac{1}{2})^4

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

Sum = 2 + 4

Sum = 6

Each term of a binomial expansion are always of the form:

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

Where n = the sum above

n = 6

Compare 15(5)^2(-\frac{1}{2})^4 to the above general form of binomial expansion

(a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......

Substitute 6 for n

(a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......

[Next is to solve for a and b]

<em>From the above expression, the power of (5) is 2</em>

<em>Express 2 as 6 - 4</em>

(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......

By direct comparison of

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

and

(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......

We have;

^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4

Further comparison gives

^nC_r = 15

a^{n-r} =(5)^{6-4}

b^r= (-\frac{1}{2})^4

[Solving for a]

By direct comparison of a^{n-r} =(5)^{6-4}

a = 5

n = 6

r = 4

[Solving for b]

By direct comparison of b^r= (-\frac{1}{2})^4

r = 4

b = \frac{-1}{2}

Substitute values for a, b, n and r in

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

(5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......

Solve for ^6C_4

(5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......

<em>Check the list of options for the expression on the left hand side</em>

<em>The correct answer is </em>(5-\frac{1}{2})^6<em />

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Allushta [10]

Answer:

The general term for the sequence can be given by the following formula:

a_n=2\,n+9

Step-by-step explanation:

If the sequence you typed starts with first term 11 and continues with terms 13, 15, 17, 19, We understand that the sequence is formed by adding 2 units to the previous term. So we are in the case of an arithmetic sequence with constant difference (d) = 2, and with first term 11.

Therefore, the nth term of this arithmetic sequence can be expressed by using the general form for an arithmetic sequence as:

a_n=a_1\,+\,(n-1)\,d\\a_n=11\,+\,(n-1)\,2\\a_n=11+2\,n-2\\a_n=2\,n+9

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A. y=2x 
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blagie [28]

The mean does not always equal the median.
The mean does not never equal the median.
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7 0
3 years ago
What is the value of the underlined digit in 207 underlined digit 7
ladessa [460]

Answer:

Its just 7

Step-by-step explanation:

Count the places. 200+7=207

3 0
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