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3 years ago

13

a political candidate hears that 65% of the voters are for him in the polls, up 40% since the last poll what percentage of voter

s were for the candidate based on the last poll math

1 answer:

Effectus [21]3 years ago

6 0

Add Midterm Elections as an interest to stay up to date on the latest Midterm ... Party ID: Democrats account for 38 percent of voters in exit poll results so far, ... The previous highs in midterm elections were 13 percent for blacks, in 2014; and 8 ... Republican House candidates in preliminary exit poll results.

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Find the value if x. Please check if I’m right!

Bad White [126]

Answer:

x=77

Step-by-step explanation:

Since both triangles are congruent, the angles will also be equal. Hence, x=77 degrees.

3 0

3 years ago

Write the equation for Chelsea's graph in

xeze [42]

Answer:

$y=-4x+16$ .

Step-by-step explanation:

From the given graph it is clear that the y-intercept is 16.

The line passes through (-2,24) and (2,8). So, slope of line is

$Slope=\dfrac{y_2-y_1}{x_2-x_1}$

$Slope=\dfrac{8-24}{2-(-2)}$

$Slope=\dfrac{-16}{4}$

$Slope=-4$

Slope intercept form of a line is

$y=mx+b$

where, m is slope and b is y-intercept.

Substitute m=-4 and b=16 in the above equation.

$y=(-4)x+(16)$

$y=-4x+16$

Therefore, the required equation is $y=-4x+16$ .

6 0

3 years ago

11. Find the average rate of change of the equation y = x2 + 4x + 1 on the interval -1 < x < 4.

coldgirl [10]

Answer:

31/5

Step-by-step explanation:

[f(4) - f(-1)] / 4-(-1)

7 0

3 years ago

P(a) = 2a -3; find p(a) = 15

Andrei [34K]

Since both is equal to p(a), you can set them as equal to each other:

15 = 2a - 3
18 = 2a
9 = a

8 0

3 years ago

A bacteria culture starts with 400 bacteria and grows at a rate proportional to its size. After 4 hours, there are 9000 bacteria

Kaylis [27]

Answer:

A) The expression for the number of bacteria is $P(t) = 400e^{0.7783t}$ .

B) After 5 hours there will be 19593 bacteria.

C) After 5.55 hours the population of bacteria will reach 30000.

Step-by-step explanation:

A) Here we have a problem with differential equations. Recall that we can interpret the rate of change of a magnitude as its derivative. So, as the rate change proportionally to the size of the population, we have

$P' = kP$

where $P$ stands for the population of bacteria.

Writing $P'$ as $\frac{dP}{dt}$ , we get

$\frac{dP}{dt} = kP$ .

Notice that this is a separable equation, so

$\frac{dP}{P} = kdt$ .

Then, integrating in both sides of the equality:

$\int\frac{dP}{P} = \int kdt$ .

We have,

$\ln P = kt+C$ .

Now, taking exponential

$P(t) = Ce^{kt}$ .

The next step is to find the value for the constant $C$ . We do this using the initial condition $P(0)=400$ . Recall that this is the initial population of bacteria. So,

$400 = P(0) = Ce^{k0}=C$ .

Hence, the expression becomes

$P(t) = 400e^{kt}$ .

Now, we find the value for $k$ . We are going to use that $P(4)=9000$ . Notice that

$9000 = 400e^{k4}$ .

Then,

$\frac{90}{4} = e^{4k}$ .

Taking logarithm

$\ln\frac{90}{4} = 4k$ , so $\frac{1}{4}\ln\frac{90}{4} = k$ .

So, $k=0.7783788273$ , and approximating to the fourth decimal place we can take $k=0.7783$ . Hence,

$P(t) = 400e^{0.7783t}$ .

B) To find the number of bacteria after 5 hours, we only need to evaluate the expression we have obtained in the previous exercise:

$P(5) =400e^{0.7783*5} = 19593.723 \approx 19593$ .

C) In this case we want to do the reverse operation: we want to find the value of t such that

$30000 = 400e^{0.7783t}$ .

This expression is equivalent to

$75 = e^{0.7783t}$ .

Now, taking logarithm we have

$\ln 75 = 0.7783t$ .

Finally,

$t = \frac{\ln 75}{0.7783} \approx 5.55$ .

So, after 5.55 hours the population of bacteria will reach 30000.

6 0

3 years ago