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3 years ago

Can someone help me with the question below. just number #1 please :)

Mathematics

2 answers:

Elenna [48]3 years ago

7 0

Answer:

${ \bf{ \bar {MN}} \: means \: length \: between \: M \: and \: N}$

MN means line joining point M to point N.

Fiesta28 [93]3 years ago

7 0

I’m pretty sure it means distance between the 2 points

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Which answer is it??

natulia [17]

A is the correct answer. PEMDAS for single step and double step equations alike.

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3 years ago

Negative nine minus negative ten?

ankoles [38]

Answer:

-9 - 10 = -19

Step-by-step explanation:

If both numbers are a negative, then add them together but keep the negative or minus sign

Hope this Helps!!!

4 0

3 years ago

ATTENTION

finlep [7]

Here!

<h2>The answer is Option A!</h2>

$(x + 2 \sqrt{3} i)(x - 2 \sqrt{3}i )$

Let's see what complex numbers are!

$(x + 2 \sqrt{3 }i )(x - 2 \sqrt{3}i ) \\ = {x}^{2} - 2 \sqrt{3} x + 2 \sqrt{3} x - {(2 \sqrt{3} i)}^{2} \\ = {x}^{2} - {(2 \sqrt{3}i) }^{2}$

Now we know,

${i}^{2} = - 1$

So!

$= {x}^{2} - 12 \times( - 1)$

$= {x}^{2} + 12$

And thus we get the answer!

3 0

3 years ago

A regular hexagon has a perimeter of 60 in. What is the hexagon's area?

Jet001 [13]

Divide the perimeter by 5 since it is regular. 60/5 = 12. Split the hexagon into a triangle and a rectangle. Find the area of each and add them together. Area of the rectangle is 12*12 = 144. To find the area of the triangle, you need to find an angle measure= y, hypotenuse = c, and a leg = a or b. An easy way to find an angle measure is to cut down the altitude and find the angle next to the base and altitude which would be 90° due to the fact that the triangle is regular also. With the regular triangle split in half, you have two right angle which form both 90-45-45 triangles. Use this formula, $A=ac \frac{siny}{2}$ --- $A=12*12 \frac{sin45}{2}$ to find the area of the triangle which equals to 50.91. Add (((144+50.91 = 194.91))) I hope I got this right if not, i'm sorry lol.

6 0

4 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

kow [346]

Answer:

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.

So 292 - 240 = 52 read below or at eight grade level, and that $n = 292, \pi = \frac{52}{292} = 0.178$

80% confidence level

So $\alpha = 0.2$ , z is the value of Z that has a pvalue of $1 - \frac{0.2}{2} = 0.9$ , so $Z = 1.28$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.149$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.207$

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

3 0

3 years ago