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Paladinen [302]
3 years ago
9

Since Marnie has bought her car,the value has gone down 15%.If her car is 13000 right now,how much was it worth when she bought

it?
Mathematics
1 answer:
Serggg [28]3 years ago
6 0
Percentage of depreciation of the car that Marie bought = 15%
Present value of the car = 13000
Let us assume that the value of the car at the time of buying = x
So
The percentage valuation of the car now = (100 - 15) percent
                                                                 = 85 percent
Then
(85/100) * x = 13000
85x = 13000 * 100
85x = 1300000
x = 1300000/85
  = 15294.12
So the actual cost of the car is 15294.12. I hope the procedure is clear enough for you to understand.
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Answer:

Option A is correct.

y = 35.4 bushels per acre when rainfall = 7.1 inches

Step-by-step explanation:

An image of the steps to obtain the equation that relates x to y is attached to this answer.

n = number of variables = 9

μₓ = mean of variable x (rainfall in inches)

μᵧ = mean of variable y (yield in bushels per acre)

σₓ = standard deviation of variable x (rainfall in inches)

σᵧ = standard deviation of variable y (yield in bushels per acre)

y = 4.379x + 4.268

when x = 7.1

y = 4.379(7.1) + 4.268 = 35.3589 = 35.4 bushels per acre.

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3 years ago
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Shalnov [3]
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the go down 1 to the left 5
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3 years ago
Question is in the picture:
cupoosta [38]
It’s 25 bc every 2 it goes up 5 dollars
4 0
2 years ago
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write a polynomial function of least degree with integral coefficients that has the given zeros. -(1/3), -i
inessss [21]

Answer:

f(x)=3x^3+x^2+3x+1

Step-by-step explanation:

If a real number -\frac{1}{3} is a zero of polynomial function, then

x-\left(-\dfrac{1}{3}\right)=x+\dfrac{1}{3}

is the factor of this function.

If a complex number -i is a xero of the polynomial function, then the complex number i is also a zero of this function and

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If the polynomial function must be with integer coefficients, then it has a form

f(x)=3x^3+x^2+3x+1

4 0
3 years ago
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sergiy2304 [10]
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