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3 years ago

The list price for a window is $220. Net price is $160. What is the trade discount rate?

Mathematics

2 answers:

Artist 52 [7]3 years ago

3 0

220-220r=160
Solve for r to get the discount rate
r=0.2727
r=0.2727×100
r=27.27%

Check
220−220×0.2727
=160

earnstyle [38]3 years ago

3 0

Answer:

Trade Discount Rate of the window is 27.27 %

Step-by-step explanation:

Given:

List Price = $ 220

Net Price = $ 160

To find: Trade Discount Rate

Trade Discount amount = 220- 160

= $ 60

Trade Discount rate = $\frac{60}{220}\times100$

= $\frac{600}{22}$

= $27.27$

Therefore, Trade Discount Rate of the window is 27.27 %

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3 years ago

Which is traveling faster, a car whose velocity vector is 201 + 25), or a car whose velocity vector is 30i, assuming that the un

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Answer:

2nd car is running faster than the first car by 2.01 units.

Step-by-step explanation:

Let's assume that

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$v_2\ =\ 30i$

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3 years ago

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3 years ago

A recent survey of 128 high school students indicated the following information about release times from school.

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Answer:

A) Interval estimate for those that want to get out earlier = (35%) ± (4%) = (31%, 39%)

Interval estimate for those that want to get out later = (39%) ± (4%) = (35%, 43%)

B) The group that wants to get out of school earlier can win after all the votes are counted if their true population proportion takes on a value that is higher than the closest true population proportion (for the group that wants to get out of school later)

That is, in the (31%, 39%) and (35%, 43%) obtained in (a), a range of (35.1%, 39%) and (35%, 38.9%) show how possible that the group that wants to get out of school earlier can win after all the votes are counted.

Step-by-step explanation:

The Interval estimate for the proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

Mathematically,

Interval estimate = (Sample proportion) ± (Margin of error)

Margin of Error is the width of the confidence interval about the proportion.

a) Find the interval estimates

i) for those that want to get out earlier and

ii) those that want to get out later.

i) Sample proportion of those that want to get out earlier = 35%

Margin of Error = 4%

Interval estimate for those that want to get out earlier = (35%) ± (4%) = (31%, 39%)

ii) Sample proportion of those that want to get out later = 39%

Margin of Error = 4%

Interval estimate for those that want to get out later = (39%) ± (4%) = (35%, 43%)

b) Explain how it would be possible for the group that wants to get out of school earlier to win after all the votes are counted.

Since the interval estimates represent the range of values that the true population proportion can take on for each group that prefer a particular option, the group that wants to get out of school earlier van have their proportion take on values between 31% and 39%. If their true population takes on a value that is highest (which is very possible from the interval estimate), and the group with the highest proportion in the sample, (the group that wants to get out of school later, whose true population proportion can take between 35% and 43%) has a true population proportion that is less than that of the group that wants to get out of school earlier, then, the group that wants to get out of school earlier can win after all the votes are counted.

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