The answer is 2,700
This is because
60
x45
------------
300
+2400
--------------
Or Use Partial Products
60. 0. 1.0x40
___________. 2.60x40
I2400 I. 30. I.
40I. I. I. 3.0x40
|---------I----------I. 4.0x5
5I. 0. I. 0. I
l____ I______I
I hope this helped because this was a lot and I mean a lot of work
V=hpir^2
I will assume that the first one is the one with radius 16 and height 40
2nd is radius 7 and height 26
1. v=hpir^2
v=40pi16^2
v=40pi256
v=10240pi cubic inches
3rd option
2.
v=hpir^2
v=26(3.14)7^2
v=26(3.14)(49)
v=1274(3.14)
v=4000.36 cubic cm
1st option
Where is the pic bro......✌✌✌.........??????how can I tell u without the picture..???
Answer:
The two column proof can be presented as follows;
Statement
Reason
1. p║q
Given
∠1 ≅ ∠11
2. ∠1 ≅ ∠9
Corresponding angles on parallel lines
3. ∠9 ≅ ∠11
Transitive property of equality
4. a║b
Corresponding angles on parallel lines are congruent
Step-by-step explanation:
The statements in the two column proof can be explained as follows;
Statement
Explanation
1. p║q
Given
∠1 ≅ ∠11
2. ∠1 ≅ ∠9
Corresponding angles on parallel lines crossed by a common transversal are congruent
3. ∠9 ≅ ∠11
Transitive property of equality
Given that ∠1 ≅ ∠11 and we have that ∠1 ≅ ∠9, then we can transit the terms between the two expressions to get, ∠9 ≅ ∠11 which is the same as ∠11 ≅ ∠9
4. a║b
Corresponding angles on parallel lines are congruent
Whereby we now have ∠9 which is formed by line a and the transversal line q, is congruent to ∠11 which is formed by line b and the common transversal line q, and both ∠9 and ∠11 occupy corresponding locations on lines a and b respectively which are crossed by the transversal, line q, then lines a and b are parallel to each other or a║b.