The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Given the inequality:
3 ≤ |x + 2| ≤ 6
Hence:
x + 2 ≤ 6, -(x + 2) ≤ 6, 3 ≤ x + 2 and 3 ≤ -(x + 2)
This gives:
x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
Find out more on equation at: brainly.com/question/2972832
#SPJ1
You can look up cymath.com it will work the problem out for you and show you the steps.
Answer:
In order of pictures,
Picture #1: 230
Picture #2: 140
Picture #3: 9.9
Picture #4: 13.5
Picture #5: 7.07
Step-by-step explanation:
I am not entirely sure that 3 - 5 are correct, but I know that 1 and 2 are correct. I am sorry if they are incorrect.
Hope that this helps!
The shape moved over 10 and up three. Is this what you’re looking for?
I am absolutely sure that the task <span> b = 3, then 3x + y = 1 and bx - y = 3 is NOT parallel, which means that the statement represented above is FALSE.
To make sure you can check it using : </span>
Hope now it's obvious. Regards!
