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ss7ja [257]
3 years ago
8

Please HELP!! PLEASE I BEG I WILL DO ANYTHING LITERALLY Create a scenario that demonstrates object permanence.

Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0
I had a very sweet dog, her name was Lilac. I had her for 13 years and unfortunately she passed away. This shows that no one object is permanent
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A Travel Weekly International Air Transport Association survey asked business travelers about the purpose for their most recent
siniylev [52]

Answer:

(a) P (p' > 0.25) = 0.

(b) P (0.15 < p' < 0.20) = 0.7784.

(c) P (133 < X < 171) = 0.2205

Step-by-step explanation:

Let <em>p</em> = proportion of business trip that were for  internal company visit.

It is provided that 19% responded that it was for an internal company visit, i.e.

<em>p</em> = 0.19.

A sample of <em>n</em> = 950 business travelers are randomly selected.

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

Thus, the distribution of \hat p is N (<em>μ</em> = 0.19, <em>σ </em>= 0.013).

(a)

Compute the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit as follows:

P (p' > 0.25) = P (Z > 4.62) = 0

*Use a <em>z</em>-table for the probability.

Thus, the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.

(b)

Compute the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit as follows:

P (0.15 < p' < 0.20) = P (-3.08 < Z < 0.77)

                               = P (Z < 0.77) - P (Z < -3.08)

                               = 0.7794 - 0.0010

                               = 0.7784

*Use a <em>z</em>-table for the probability.

Thus, the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.7784.

(c)

Compute the proportion of <em>X</em> = 133  and <em>X</em> = 171 as follows:

p' = 133/950 = 0.14

p' = 171/950 = 0.18

Compute the value of P (0.14 < p' < 0.20) as follows:

P (0.14 < p' < 0.18) = P (-3.85< Z < -0.77)

                               = P (Z < -0.77) - P (Z < -3.85)

                               = 0.2206- 0.0001

                               = 0.2205

*Use a <em>z</em>-table for the probability.

Thus, the probability that between 133 and 171 of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.2205.

7 0
3 years ago
Starting at sea level, a submarine descended at a constant rate to a depth of − 4/5 mile relative to sea level in 3 minutes.
Jobisdone [24]
If it were 4 then it would be 1 1/3 for one minute
5 0
3 years ago
Read 2 more answers
544484454545454c454545x454544d5454d5w4ds5d45x45a45s4544444444444444444444444444444444444444449999999999999999xx599999999999994x5
MAXImum [283]

Answer:

uh. the answer to this is

8 0
3 years ago
Read 2 more answers
If gokus power is 100 trillion then he looses 567 billion how much does he have.
julia-pushkina [17]

Answer:

9.9433e+13

Step-by-step explanation:

Mark me brainliest

4 0
3 years ago
Read 2 more answers
F
Burka [1]

Answer:

12

Step-by-step explanation:

F \alpha \frac{1}{d^{2} }

F = \frac{K}{d^{2} }

When F = 18; d = 2

18 = \frac{K}{2^{2} }

18 = \frac{K}{4}

Cross multiply;

18 x 4 = K

72 = K

There the equation connecting F and d^{2} is

F = \frac{72}{d}

Now, Find F when d = 6

All you do is to substitute d = 6 in to F = \frac{72}{d}

F = \frac{72}{6}

Therefore;

F = 12

Please mark me brainiest if correct.

6 0
3 years ago
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