The distance in kilometers in scientific notation 
<h3>Scale factors</h3>
Scale factors are values or constants multiplied with a variable
If Alvin and Simon raced a distance of
kilometers and they need to race 7 times that distance in a kilometer, the distance traveled will be:
- Distance travelled =

- Distance travelled =

Hence the distance in kilometers in scientific notation 
Learn more on distance here: brainly.com/question/23848540
Answer: A. Wed to Fri
We have a bunch of natural numbers and we're told a pair is in the ratio 2:5.
For natural numbers to have this ratio, the left number will be a multiple of two and the right number will be a multiple of five.
Our only option for a multiple of 5 is 15, Friday. So we have
2:5 = x:15
and x = 15*2/5 = 6
which was Wednesday's number. So we get Wed:Fri=6:15=2:5.
Answer:
This is curve sketching which is used in math
Step-by-step explanation:
we can see a graph plotting with the equation...of all sides
Answer:
85 units^2 = Area of Blue Square
and
x = 5 units
Step-by-step explanation:
To do this we use the Pythagorean theorem (a^2 + b^2 = c^2). a and b represent the legs of the triangle whereas c represents the longest side of the triangle, or the hypotenuse.
Since we know the area of a square is the side length multiplied by itself (or the side length squared),
is the side length of the pink square and
is the side length of the green square.
That means a =
and b =
, so...

35 + 50 = c^2
85 = c^2

Now we need to square the square root of 85 to find the area of the blue square.

85 units^2 = Area of Blue Square
To solve the other question we use the same formula again.

x = 5 units
This is a problem of Permutations. We have 3 cases depending on the number of B's. Since no more than three B's can be used we can use either one, two or three B's at a time.
Case 1: Five A's and One B
Total number of letters = 6
Total number of words possible = 
Case 2: Five A's and Two B's
Total number of letters = 7
Total number of words possible = 
Case 3: Five A's and Three B's
Total number of letters = 8
Total number of words possible = 
Total number of possible words will be the sum of all three cases.
Therefore, the total number of words that can be written using exactly five A's and no more than three B's (and no other letters) are 6 + 21 + 56 = 83