Step-by-step explanation:
7=4y-13
7+13=4y
20/4=y
5=y
If shapes are congruent, then they are mathematically equal (same dimensions, angles etc.). So just locate where the angle x is on both triangles, it should have a value on or a calculable value on the other. If you provide us with the actual sheet I could walk you through it.
An irrational number is a number that cannot be expressed in a fraction form while a rational number can.
an example of an irrational numbers are repeating numbers such as 0.77777... and examples of rational numbers are decimals such as 0.20, whole numbers such as 5, and fractions like 2/3
hope this helps a bit.
The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is 
<u>Solution:</u>
Given, expression is 
We have to write in as single logarithm by simplifying it.
Now, take the given expression.

Rearranging the terms we get,







Hence, the simplified form 
Answer:
The correct answer is 1 pitcher.
Step-by-step explanation:
Oscar sold 2 pitchers of lemon are from his lemonade stand on Friday.
On Saturday, he sold
as much lemonade as on Friday.
The number of pitchers of lemon from the lemonade stand which Oscar sold on Saturday is given by
× 2 = 1 pitcher.
Thus Oscar sold 1 pitcher on Saturday which is half of the number of pitchers of lemon he could sell on Friday.