9514 1404 393
Answer:
5 hours
Step-by-step explanation:
A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.
The first day, the charge is $3 more than $12 per hour.
The second day, the charge is $12 less than $15 per hour.
The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...
$15/($3/h) = 5 h
The charges are the same after 5 hours.
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If you write equations for the charges, they will look like ...
y1 = 15 + 12(x -1)
y2 = 3 + 15(x -1)
Equating these charges, we have ...
15 +12(x -1) = 3 + 15(x -1)
12x +3 = 15x -12 . . . . . . . . eliminate parentheses
15 = 3x . . . . . . . . . . add 12-12x
x = 15/3 = 5 . . . . . . divide by 3
You might notice that the math here is very similar to that described in words, above.
The charges are the same after 5 hours.
The equation are y = 0.59x + 29.95 for company A and y = 0.79x + 19.95 for company B.
<h3>
Linear equation</h3>
Linear equation is in the form:
y = mx + b
where y,x are variables, m is the rate of change and b is the initial value of y.
Let y represent the total cost of rental for each truck in x hours.
From the table, for company A:
For company B:
The equation are y = 0.59x + 29.95 for company A and y = 0.79x + 19.95 for company B.
Find out more on linear equation at: brainly.com/question/14323743
f(x) = -720h + 10080
10080 is the total amount of water in the pool, 720 is the amount of water you lose each hour.
"h" is the number of hours the pool has been draining, and since you know the pool has been draining for 12 hours, you can plug in 12 for "h".
f(x) = -720h + 10080
f(x) = -720(12) + 10080
f(x) = -8640 + 10080
f(x) = 1440
After 12 hours of draining, 1440 is the amount of water left in the pool. (I don't know the units [ex: gallons, etc.])
Answer:
She will be around 11 yrs old
Step-by-step explanation: 45 divided by 4 is 11.25
