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stira [4]
4 years ago
12

As element of group 1 on the periodic table are considered in order of increasing atomic radius, the ionization energy of each s

uccessive element generally, A. Decreases B. Remains the same C. Increases
Chemistry
2 answers:
Misha Larkins [42]4 years ago
5 0

Answer:

The ionization energy of each successive element generally decreases

Explanation:

The ionization energy increases in the periods of the periodic table and decreases in the groups. If the atom is very small, we will need a lot of energy to release the electron, while if the atom is larger the energy will be greater.

Darina [25.2K]4 years ago
5 0

Answer:

the relative electronegativity increases, and the atomic radius decreases

Explanation:

Elements in Period 2 have atomic numbers ranging from 3 through 10. Look at Reference Table S. The electronegativity value increases while the atomic radius decreases for the elements of the second period with increasing atomic number.

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A chemist must prepare 575.mL of 1.00M aqueous sodium carbonate Na2CO3 working solution. He'll do this by pouring out some 1.58M
igor_vitrenko [27]

Answer : The volume in mL of the sodium carbonate stock solution is 364 mL.

Explanation :

According to dilution law:

M_1V_1=M_2V_2

where,

M_1 = molarity of aqueous sodium carbonate

M_2 = molarity of aqueous sodium carbonate stock solution

V_1 = volume of aqueous sodium carbonate

V_2 = volume of aqueous sodium carbonate stock solution

Given:

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V_1 = 575 mL

V_2 = ?

Now put all the given values in the above formula, we get:

1.00M\times 575mL=1.58M\times V_2

V_2=363.92mL\approx 364mL

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8 0
3 years ago
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4 years ago
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victus00 [196]

Answer:

Option B is correct.

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