Question

A chemist must prepare 575.mL of 1.00M aqueous sodium carbonate Na2CO3 working solution. He'll do this by pouring out some 1.58M aqueous sodium carbonate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the sodium carbonate stock solution that the chemist should pour out. Round your answer to 3 significant digits.

Answer 1

Answer : The volume in mL of the sodium carbonate stock solution is 364 mL.

Explanation :

According to dilution law:

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of aqueous sodium carbonate

$M_2$ = molarity of aqueous sodium carbonate stock solution

$V_1$ = volume of aqueous sodium carbonate

$V_2$ = volume of aqueous sodium carbonate stock solution

Given:

$M_1$ = 1.00 M

$M_2$ = 1.58 M

$V_1$ = 575 mL

$V_2$ = ?

Now put all the given values in the above formula, we get:

$1.00M\times 575mL=1.58M\times V_2$

$V_2=363.92mL\approx 364mL$

Therefore, the volume in mL of the sodium carbonate stock solution is 364 mL.