Answer: see table below
<u>Step-by-step explanation:</u>
Newton's Law of Cooling
Tf=Ts+(Ti-Ts)e^(-kt) where Tf is temp at time t, Ts is temp of surroundings, Ti is temp of object/fluid. So we need to find k first.
200=68+(210-68)e^(-10k)
132=142e^(-10k)
132/142=e^(-10k)
ln(132/142)=-10k
k=-ln(132/142)/10
k≈0.0073 so
T(t)=68+142e^(-0.0073t) so how long until it reaches 180°?
180=68+142e^(-0.0073t)
112=142e^(-0.0073t)
112/142=e^(-0.0073t)
ln(112/142)=-0.0073t
t= -ln(112/142)/(0.0073)
t≈32.51 minutes
4h−6=22
1. Add 6 to both sides.
<span><span><span><span>4h</span>−6</span>+6</span>=<span>22+6</span></span>
<span><span>4h</span>=28
</span>2.Divide both sides by 4.
<span><span><span>4h/</span>4</span>=<span>28/4
</span></span><span>h=<span>7
</span></span>−8s+1=33
1: Subtract 1 from both sides.
−8s+1−1=33−1
−8s=32
2: Divide both sides by -8.
−8s/−8=32/−8
<span>s=-4
</span><span><span><span>
−<span>4w</span></span>−4</span>=8
</span>Step 1: Add 4 to both sides.
<span><span><span><span>−<span>4w</span></span>−4</span>+4</span>=<span>8+4
</span></span><span><span>−<span>4w</span></span>=12
</span>2: Divide both sides by -4.
<span><span><span>−<span>4w/</span></span><span>−4</span></span>=<span>12/<span>−4
</span></span></span><span>w=<span>−3</span></span>
<span>
Step 1: Simplify both sides of the equation.</span>
<span><span><span><span>1/7</span>b</span>+5</span>=<span>−2
</span></span> 2: Subtract 5 from both sides.
<span><span><span><span><span>1/7</span>b</span>+5</span>−5</span>=<span><span>−2</span>−5
</span></span><span><span><span>17</span>b</span>=<span>−7
</span></span>3: Multiply both sides by 7.
<span><span>7*<span>(<span><span>1/7</span>b</span>)</span></span>=<span><span>(7)</span>*<span>(<span>−7</span>)
</span></span></span><span>b=<span>−49</span></span>
Answer:
Step-by-step explanation:
