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Harman [31]
3 years ago
6

If $1600 earned simple interest of $56.24 in 2 months, what was the simple interest rate? The simple interest rate is % (Do not

round until the final answer. Then round to the nearest tenth as needed.)
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer:

The interest rate is of 21.09% a year.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly) and t is the time.

So, for our problem, we have:

If $1600 earned simple interest of $56.24 in 2 months, so:

P = 1600, E = 56.24.

The interest value is a yearly value, however the time is given in months. This means that we have to divide the time by 12(that is the number of months in a year). So

t = \frac{2}{12} = \frac{1}{6}

Solution:

56.24 = 1600*I*\frac{1}{6}

1600I = 6*56.24

1600I = 337.44

I = \frac{337.44}{1600}

I = 0.2109

The interest rate is of 21.09% a year.

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(a) E(x) = -0.081  S.D = 3

(b) E(x) = -0.081  S.D = 1.73

(c) it is less risky to bet $1 in three different rounds as compared to betting $3 in a single round.    

Step-by-step explanation:

(a) You bet $3 on a single round which means that if you win the game, your amount will double ($6), your profit will be $3. Whereas, if you lose the round, your profit will be -$3. You can only bet on red or black and both have 18 slots each.

So, the probability of landing the ball in a red/black slot = 18/37. This is the probability of winning. The probability of losing can be calculated as 1-18/37 = 19/37.

We can make a probability distribution table:

x                    3             -3

P(X=x)         18/37      19/37

Expected value E(x) can be calculated as:

E(x) = ∑ x.P(x)

      = (3)(18/37) + (-3)(19/37)

E(x) = -0.081

Standard deviation can be calculated by the following formula:

Var(x) = E(x²) - E(x)²

S.D = √Var(x)

We need to first calculate E(x²).

E(x²) = ∑x².P(x)

       = (3)²(18/37) + (-3)²(19/37)

       = (9)(18/37) + (9)(19/37)

E(x²) = 9

Var(x) = E(x²) - E(x)²

         = 9 - (-0.081)²

Var(x) = 8.993

S.D = √8.993

S.D = 2.99 ≅ 3

(b) Now, the betting price is $1 and 3 rounds are played. We will compute the expectation for one round and then add it thrice to find the expectation for three rounds. Similarly, for the standard deviations, we will add the individual variances and then consider the square root of it.

E(x) = ∑ x.P(x)

      = (1)(18/37) + (-1)(19/37)

E(x) = -0.027

Standard deviation can be calculated by the following formula:

Var(x) = E(x²) - E(x)²

S.D = √Var(x)

We need to first calculate E(x²).

E(x²) = ∑x².P(x)

       = (1)²(18/37) + (-1)²(19/37)

       = (1)(18/37) + (1)(19/37)

E(x²) = 1

Var(x) = E(x²) - E(x)²

         = 1 - (-0.027)²

Var(x) = 0.9992

The expectation for one round is -0.027

For three rounds,

E(x₁ + x₂ + x₃) = E(x₁) + E(x₂) + E(x₃)

                     = (-0.027) + (-0.027) + (-0.027)

E(x₁ + x₂ + x₃) = -0.081

Similarly, the variance for one round is 0.9992.

Var (x₁ + x₂ + x₃) = Var(x₁) + Var(x₂) + Var(x₃)

                           = 0.9992 + 0.9992 + 0.9992

Var (x₁ + x₂ + x₃) = 2.9976

S.D = √2.9976

S.D = 1.73              

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Answer:

1.8

is the median

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