Which statement is true about figures ABCD and A′B′C′D′? A polygon ABCD has A at ordered pair 2, negative 2, B at 1, negative 4,
C at 0 and negative 2, D at 1 and negative 1. A polygon A prime B prime C prime D prime has A prime at ordered pair negative 2, negative 2, B prime at ordered pair negative 1, negative 4, C prime at ordered pair 0, negative 2 and D prime at ordered pair negative 1, negative 1. A′B′C′D′ is obtained by rotating ABCD counterclockwise by 180 degrees about the origin and then reflecting it across the x-axis. A′B′C′D′ is obtained by translating ABCD 2 units up and then reflecting it about the y-axis. A′B′C′D′ is obtained by translating ABCD 2 units up and then reflecting it about the x-axis. A′B′C′D′ is obtained by rotating ABCD counterclockwise by 180 degrees about the origin and then reflecting it across the y-axis.
A'B'C'D' is obtained by rotating ABCD 180° counterclockwise about the origin and then reflecting it across the x-axis.
A(2, -2) is mapped to A'(-2, -2) B(1, -4) is mapped to B'(-1, -4) C(0, -2) is mapped to C'(0, -2) D(1, -1) is mapped to D'(-1, -1)
If we rotate counterclockwise 180°, every point (x, y) is mapped to (-x, -y): A(2, -2) gets mapped to (-2, 2) B(1, -4) gets mapped to (-1, 4) C(0, -2) gets mapped to (0, 2) D(1, -1) gets mapped to (-1, 1)
Reflecting these images across the x-axis will then map (x, y) to (x, -y): (-2, 2) gets mapped to (-2, -2) (-1, 4) gets mapped to (-1, -4) (0, 2) gets mapped to (0, -2) (-1, 1) gets mapped to (-1, -1)
first graph the y-intercept. when x=0, y=-3, so graph a point at (0,-3). since this is a straight line, we only need to graph one more point to find the line. since the slope is -1/5, we can plug in 5 for x to find integer points. when x=5, y=-1/5*5 -3 = -1-3=-4. so another point on the line is (5,-4). then just connect the two points to find the line
