Triangle ABC was translated to from A’B’C’

Write as many equations as possible that could represent the relationship between the ages of the two children in each family de

Daniel [21]

Answer:

Step-by-step explanation:

a) Here we have:

"In Family A, the youngest child is 7 years younger than the oldest, who is 18"

Let's define:

Y = age of the youngest child.

O = age of the oldest child.

Then we know that:

Y = O - 7

O = 18

Then we can replace the second equation into the first one:

Y = 18 - 7 = 11.

b) Here we have:

"In Family B, the middle child is 5 years older than the youngest child."

Let's define:

Y = age of the youngest child.

M = age of the middle child.

Here we have only one equation:

M = Y + 5.

4 0

3 years ago

The inequality of the graph

fiasKO [112]

Answer:

$\displaystyle y > 4x - 2$

Step-by-step explanation:

Starting from the y-intercept of $\displaystyle [0, -2],$ you do $\displaystyle \frac{rise}{run}$ by either moving four blocks south over one block west or four blocks north over one block east [west and south are negatives]. Next, we have to determine the types of inequality symbols that are suitable for this graph, which will be less than and greater than since this is a dashed line graph. We then use the zero-interval test [test point (0, 0)] to ensure whether we shade the opposite portion [portion that does not contain the origin] or the portion that DOES contain the origin. At this step, we must verify the inequalities as false or true:

Greater than

$\displaystyle 0 > 4[0] - 2 → 0 > -2$ ☑

Less than

$\displaystyle 0 < 4[0] - 2 → 0 ≮ -2$

This graph is shaded in the portion of the origin, so you would choose the greater than inequality symbol to get this inequality:

$\displaystyle y > 4x - 2$

I am joyous to assist you anytime.

3 0

4 years ago

Box of cereal contains 23.4 ounces. Cost $5.49. What’s the cost per ounce?

Sedaia [141]

Answer:

it 4.262295082

Step-by-step explanation:

you have to divid the ounces by the cost

6 0

3 years ago

This problem uses the teengamb data set in the faraway package. Fit a model with gamble as the response and the other variables

hichkok12 [17]

Answer:

A. 95% confidence interval of gamble amount is (18.78277, 37.70227)

B. The 95% confidence interval of gamble amount is (42.23237, 100.3835)

C. 95% confidence interval of sqrt(gamble) is (3.180676, 4.918371)

D. The predicted bet value for a woman with status = 20, income = 1, verbal = 10, which shows a negative result and does not fit with the data, so it is inferred that model (c) does not fit with this information

Step-by-step explanation:

to)

We will see a code with which it can be predicted that an average man with income and verbal score maintains an appropriate 95% CI.

attach (teengamb)

model = lm (bet ~ sex + status + income + verbal)

newdata = data.frame (sex = 0, state = mean (state), income = mean (income), verbal = mean (verbal))

predict (model, new data, interval = "predict")

lwr upr setting

28.24252 -18.51536 75.00039

we can deduce that an average man, with income and verbal score can play 28.24252 times

using the following formula you can obtain the confidence interval for the bet amount of 95%

predict (model, new data, range = "confidence")

lwr upr setting

28.24252 18.78277 37.70227

as a result, the confidence interval of 95% of the bet amount is (18.78277, 37.70227)

b)

Run the following command to predict a man with maximum values for status, income, and verbal score.

newdata1 = data.frame (sex = 0, state = max (state), income = max (income), verbal = max (verbal))

predict (model, new data1, interval = "confidence")

lwr upr setting

71.30794 42.23237 100.3835

we can deduce that a man with the maximum state, income and verbal punctuation is going to bet 71.30794

The 95% confidence interval of the bet amount is (42.23237, 100.3835)

it is observed that the confidence interval is wider for a man in maximum state than for an average man, it is an expected data because the bet value will be higher than the person with maximum state that the average what you carried s that simultaneously The, the standard error and the width of the confidence interval is wider for maximum data values.

(C)

Run the following code for the new model and predict the answer.

model1 = lm (sqrt (bet) ~ sex + status + income + verbal)

we replace:

predict (model1, new data, range = "confidence")

lwr upr setting

4,049523 3,180676 4.918371

The predicted sqrt (bet) is 4.049523. which is equal to the bet amount is 16.39864.

The 95% confidence interval of sqrt (wager) is (3.180676, 4.918371)

(d)

We will see the code to predict women with status = 20, income = 1, verbal = 10.

newdata2 = data.frame (sex = 1, state = 20, income = 1, verbal = 10)

predict (model1, new data2, interval = "confidence")

lwr upr setting

-2.08648 -4.445937 0.272978

The predicted bet value for a woman with status = 20, income = 1, verbal = 10, which shows a negative result and does not fit with the data, so it is inferred that model (c) does not fit with this information

4 0

3 years ago

Write the set of points from −6−6 to 33 but excluding −2−2 and 33 as a union of intervals:

Softa [21]

In this question, we have to write the set of points from -6 to 3 but excluding -2 and 3 as a union of intervals .

For union, we use U.

For the points that we have to exclude , we put parenthesis on there side that is ().

Therefore the required interval form is

$[-6,-2)U(-2,3)$

As we see that () are used with -2 and 3 . And that's the required interval form .

5 0

3 years ago