Question

What is the minimum mass of sodium hydroxide required to neutralize a solution that was prepared by dissolving 9.16 g of hydrochloric acid (HCl) in excess water?

Answer 1

Answer:

10.04 g of NaOH is required for neutralization

Explanation:

neutralization reaction:

$NaOH+HCl\rightarrow NaCl+H_{2}O$

Molar mass of NaOH = 40 g/mol

Molar mass of HCl = 36.5 g/mol

So, 9.16 g of HCl = $\frac{9.16}{36.5}$ moles of HCl = 0.251 moles of HCl

According to neutralization reaction, 1 mol of NaOH is required to neutralize 1 mol of HCl

So, 0.251 moles of NaOH are required to neutralize 0.251 moles of HCl

So mass of NaOH required for neutralization = ($0.251\times 40$) g = 10.04 g