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viktelen [127]
2 years ago
10

Calculate how many moles of nh3 form when each quantity of reactant completely reacts?

Chemistry
1 answer:
anygoal [31]2 years ago
6 0

3.6 moles NH_{3} required when each quantity of reactant completely reacts.

The ratio of the mole quantities of any two compounds present in a balanced chemical reaction is known as the mole ratio. A reaction's product yield can be predicted using mole ratios, as can the amount of reactant required to produce a specific amount of result.

The balanced chemical equation is :

3N_{2} H_{4}(l) → 4NH_{3}(g) + N_{2}(g)

Given is = 2.6 mol N_{2} H_{4}

As we see, 3 moles of N_{2} H_{4} reacts with  4 moles of NH_{3}.

Therefore,

n( NH_{3}) = n(  N_{2} H_{4} ) × \frac{4}{3}

n( NH_{3}) = 2.6mol^{*} \frac{4mol}{3mol}

n( NH_{3}) = 3.6 moles.

Therefores, 3.6 moles NH_{3} required when each quantity of reactant completely reacts.

Learn more about moles here;

brainly.com/question/20486415

#SPJ4

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in the problem the product formed after radiation was Pb-206. isotopes of lead include Pb-204, Pb-206, Pb-207, Pb-208. they all have atomic number 82. which means the radiation cannot be ∝ or β since both radiations will alter the atomic number of the parent nucleus.

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