Question

Calculate how many moles of nh3 form when each quantity of reactant completely reacts?

Answer 1

3.6 moles $NH_{3}$ required when each quantity of reactant completely reacts.

The ratio of the mole quantities of any two compounds present in a balanced chemical reaction is known as the mole ratio. A reaction's product yield can be predicted using mole ratios, as can the amount of reactant required to produce a specific amount of result.

The balanced chemical equation is :

$3N_{2} H_{4}$(l) → $4NH_{3}$(g) + $N_{2}$(g)

Given is = 2.6 mol $N_{2} H_{4}$

As we see, 3 moles of $N_{2} H_{4}$ reacts with  4 moles of $NH_{3}$.

Therefore,

n( $NH_{3}$) = n(  $N_{2} H_{4}$ ) × $\frac{4}{3}$

n( $NH_{3}$) = $2.6mol^{*} \frac{4mol}{3mol}$

n( $NH_{3}$) = 3.6 moles.

Therefores, 3.6 moles $NH_{3}$ required when each quantity of reactant completely reacts.

Learn more about moles here;

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