Question

Consider an insulated container in which water (2.58 g) solidifies at 0 oC and 1 atm on the surface of a 55 g aluminum block. Assuming that the heat transfer occurs only between the water and the metal, estimate the change in temperature of the aluminum block.

Answer 1

Answer:

17.41°C is the change in temperature of the aluminum block.

Explanation:

Latent heat of fusion water = 334 J/g

Heat required to freeze 1 gram of water = -334 J

Heat required to freeze 2.58 grams of water = Q

$Q=2.58 g\times (-334 J/g)=-861.72 J$

Heat lost by water will be equal to heat gained by the aluminum block

$Q'=-Q$

$Q'= -(-861.72 J)=861.72 J$

Formula used to calculate heat absorbed by substance:

$Q=mc\Delta T$

Where:

Q = heat absorbed by substance

c = specific heat of substance

m = Mass of the substance  

ΔT = change in temperature of the substance

We have :

Mass of aluminum block= m= 55 g

Heat capacity of aluminum = c = 0.9 J/g°C

Change in temperature of the aluminum block= ΔT = ?

Heat absorbed by the aluminum = Q'

$861.72 J=55 g\times 0.9 J/g^oC\times \Delta T$

$\Delta T=17.41 ^oC$

17.41°C is the change in temperature of the aluminum block.