The equation ofa line that passes throug (x1,y1) and has s slope of m is
y-y1=m(x-x1)
given
point is (-1,-3) and slope=4
y-(-3)=4(x-(-1)) or
y+3=4(x+1)
B is the answer
If x is the hypotenuse then
hyp^2 = 4^2 + 5^2
hyp^2 = 41
hypotenuse =
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<span>
6.403124
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if x is a leg then
leg^2 = 5^2 - 4^2
leg^2 = 25 - 16
leg^2 = 9
leg =3
Answer:
y=1/2x+2
Step-by-step explanation:
