The solution would be ... m = <span>√2 - 48 over 16. Have a good day :)</span>
Answer:
x/y=1/4
Step-by-step explanation:
3x+2y=3y-2
3x=3y-2y-2
3x=y-2
y=3x+2
x+y=10
x+3x+2=10
4x+2=10
4x=10-2
4x=8
x=8/4
x=2
2+y=10
y=10-2
y=8
x/y=2/8=1/4
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Answer:
x = 50°
Step-by-step explanation:
180° - 80° = 100°
100° ÷ 2 = 50°
50° + 50° + 80° = 180°
