1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ikadub [295]
2 years ago
10

Find the length of x when you have 35 and 12

Mathematics
1 answer:
olga2289 [7]2 years ago
7 0

When I asked 35 what is the length of x is he answered it was 45. I didn't believe him so I went to his wife, 12 and asked her how long was x. She also said 45. I was like ooh. Cool. OK. good. Radical.

You might be interested in
1. Divide 6x^4 + 2x^3 – 6x^2 – 14x – 1 by 3x + 1 by using synthetic division or long division. Show all
iris [78.8K]
                  2x^3 - 2x - 4

3x + 1        6x^4 + 2x^3 - 6x^2 - 14x - 1
                  6x^4 + 2x^3
                
                                       -6x^2 - 14x - 1
                                       -6x^2 - 2x
     
                                                 -12x - 1
                                                 -12x - 4
 
                                                           3

3x + 1 is not a factor of the dividend because, dividing the dividend with 3x + 1 gives a remainder.
5 0
4 years ago
Bob and Cam are scuba diving. Bob is 15 meters below the surface of the water. Cam is 4 meters above Bob.
Lana71 [14]

Answer: -11 meters

Step-by-step explanation:

so for the waters surface, we are going to call that 0. if bob is at 15 meters below 0, then -15+4=-11, so he would be at-11 meters in relation to the waters surface.

6 0
3 years ago
If you make 1170 points out of 1800 what grade would I have​
insens350 [35]

Answer:

req grade=35%

Step-by-step explanation:

req grade=\frac{1800-1170}{1800}\times100

req grade=\frac{63000}{1800}

req grade=35% answer

5 0
4 years ago
Log16^*+log4^*+log2^*=7​
ale4655 [162]

Answer:

x = 16

Step-by-step explanation:

Given

log_{16}(x) + log_4(x) + log_2(x) = 7

Required

Solve for x

log_{16}(x) + log_4(x) + log_2(x) = 7

Change base of 16 and base of 4 to base 2

\frac{log_2(x)}{log_2(16)} + \frac{log_2(x)}{log_2(4)} + log_2(x) = 7

Express 16 and 4 as 2^4 and 2^2 respectively

\frac{log_2(x)}{log_2(2^4)} + \frac{log_2(x)}{log_2(2^2)} + log_2(x) = 7

The above can be rewritten as:

\frac{log_2(x)}{4log_22} + \frac{log_2(x)}{2log_22} + log_2(x) = 7

log_22 = 1

So, we have:

\frac{log_2(x)}{4*1} + \frac{log_2(x)}{2*1} + log_2(x) = 7

\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x) = 7

Multiply through by 4

4(\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x)) = 7 * 4

log_2(x) + 2}log_2(x) + 4log_2(x) = 28

7log_2(x) = 28

Divide through by 7

\frac{7log_2(x)}{7} = \frac{28}{7}

log_2(x) = 4

Apply the following law of logarithm:

<em>If </em>log_ab = c<em> </em><em>Then </em>b = a^c<em></em>

So, we have:

x = 2^4

x = 16

6 0
3 years ago
Jozef works in a factory and is paid £352 a week. He works 40 hours a week. What is his hourly rate?
miskamm [114]

Answer:

Step-by-step explanation:

6 0
3 years ago
Other questions:
  • Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!
    9·2 answers
  • Find the area of the shaded region. (Plz show work)
    10·1 answer
  • WILL AWARD BRAINLIEST <br><br><br> What is the value of a?
    9·1 answer
  • A dog walker charges a flat rate of $6 per walk plus an hourly rate of $30. How much does the dog walker charge for a 45 minute
    15·1 answer
  • A landscaping company needs
    6·1 answer
  • Can some also explain it to me how to identify if it’s continuous exponential
    12·1 answer
  • I will give brainiest if correct please hurry!!
    10·1 answer
  • Find the slope of the line of best fit shown below.​
    6·1 answer
  • MAM I NEED HELP WHAT DO I NEED TO PUT!!!!!
    5·1 answer
  • *Ahem*<br> HELP ME PLEASE! <br> WILL GIVE BRAINLIEST
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!