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2 years ago

PLEASE HELP ME!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

attashe74 [19]2 years ago

4 0

The missing angle is 28 degrees.
All triangles angles add up to 180 degrees.
47 + 31 = 78
180 - 78 = 102
102 + 50 = 152
180 - 152 = 28

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Calculate the area of the square shown below (HARD)

sergey [27]

Check the picture below.

recall that in a square, all sides are equal, so if we make b = a, then we get that for one side, also recall that the area of a rectangle is length*width, so in this case,

$\bf \stackrel{\textit{area of the square}}{\stackrel{length}{5\sqrt{2}}\cdot \stackrel{width}{5\sqrt{2}}}\implies 25(\sqrt{2})^2\implies 25\cdot 2\implies 50$

7 0

2 years ago

Can anybody explain how to subtract mixed fractions?

Ilya [14]

Answer:

convert the mixed fractions to improper fractions (where the numerator is greater than or equal to the denominator): multiply the whole number part by the fraction's denominator, add that to the numerator, write the result on top of the denominator.
if the denominators are not the same, work out the common denominator and rewrite the fractions with the same denominators
subtract by subtracting the numerators and writing the result over the denominator
convert back to mixed fractions by dividing the numerator by the denominator, write down the whole number answer, write down the remainder above the denominator.

Example

$3\frac23-1\frac45$

convert to improper fractions:

$\dfrac{3 \times 3+2}{3}-\dfrac{1 \times 5+4}{5}=\dfrac{11}{3}-\dfrac{9}{5}$

common denominator = 3 × 5 = 15, so:

$\dfrac{11}{3}-\dfrac{9}{5}=\dfrac{11\times 5}{3\times 5}-\dfrac{9\times 3}{5\times 3}=\dfrac{55}{15}-\dfrac{27}{15}$

subtract:

$\dfrac{55}{15}-\dfrac{27}{15}=\dfrac{55-27}{15}=\dfrac{28}{15}$

convert back to mixed fractions:

$28 \div 15=1 \textsf{ remainder }13=1 \frac{13}{15}$

7 0

2 years ago

Read 2 more answers

How do you solve it?

MatroZZZ [7]

Answer:

i: x=-2, x=1

ii: x=-1/2

Step-by-step explanation:

Quadratic form:

You solve i by using FOIL (First, Outside, Inside, Last) because it is a multiplication problem.

$(x+2)(x-1)=0$

"first" would be $x*x$ , which would equal $x^{2}$

"outside" would be $x*-1$ , which would equal $-1x, or -x$

"inside" would be $2*x$ , which would equal $2x$

"last" would be $2*-1$ , which would equal $-2$

Now you need to combine the terms so that they are one after the other

$x^{2}-x$ $+2x-2$

Combine like terms, and you should get:

$x^{2} +x-2$

i Solution

You need to get the variable by itself.

Subtract two from both sides

$x+2=0\\x=-2$

Add one to both sides.

$x-1=0\\x=1$

ii Solution

Add all the terms.

$x+2+x-1=0\\2x+1=0\\2x=-1\\x=-\frac{1}{2}$

8 0

3 years ago

PLEASE HELP ME ASAP!!

solong [7]

We have to find midpoint M of the diagonal AC (or BD, there is no difference) so:

$M=\left(\dfrac{x_A+x_C}{2},\dfrac{y_A+y_C}{2}\right)=\left(\dfrac{-2+4}{2},\dfrac{4+(-2)}{2}\right)=\left(\dfrac{2}{2},\dfrac{2}{2}\right)=\\\\\\=\boxed{(1,1)}$

5 0

3 years ago

Find the area of the composite figure

SOVA2 [1]

Answer:

The answer is 49

Step-by-step explanation:

the square = 10×4= 40

The triangle = 6×3= 18 >> 18÷2 = 9ft

40+9= 49ft

4 0

2 years ago