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2 years ago

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4. An airplane descends at a rate of 1,400 feet per minute. Once the airplane starts its descent, what will be its change in ele

vation after 4 minutes?

1 answer:

Evgesh-ka [11]2 years ago

5 0

Answer:

5600 feet

Step-by-step explanation:

If it is dropping 1400 every minute then to find the elevation at 4 minutes, you have to multiply 1400 with 4.

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7 divided by 2-4.5x3+8

lord [1]

Answer:

2-4.5×3+8=-3.8

-3.8÷7=-0.5

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

X+y=3 x=6-4y using substitution

kenny6666 [7]

Givens

x + y = 3

x =6 - 4y

Solution

Use the top equation to substitute for x in the second equation.

x = 3 - y

Put this result into the second given equation and solve for y

3 - y = 6 - 4y Add 4y to both sides.

3 - y + 4y = 6 Combine on the left

3 + 3y = 6 Subtract 3 from both sides

3 - 3 + 3y = 6 - 3 Combine

3y = 3 Divide by 3

3y/3 = 3/3 Combine

y = 1

=========================

x + y = 3 but y = 1

x + 1 = 3 Subtract 1 from both sides.

x + 1 - 1 =3 - 1

x = 2

Answer

x = 2

y = 1

4 0

2 years ago

Read 2 more answers

P(x)= 3x^3-5x^2-14x-4

nexus9112 [7]

$\displaystyle\\
P(x)=3x^3-5x^2-14x-4\\\\
D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\
\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\
3x^3-5x^2-14x-4=0\\\\
$

$\displaystyle\\
\text{Verification}\\\\
3x^3-5x^2-14x-4=\\\\
=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\
=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\
 =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\
\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\
\Longrightarrow~~~P(x)~\vdots~(3x+1)$

$\displaystyle\\
3x^3-5x^2-14x-4=0\\
~~~~~-5x^2 = x^2 - 6x^2\\
~~~~~-14x =-2x-12x \\
3x^3+x^2 - 6x^2-2x-12x-4=0\\
x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\
(3x+1)(x^2-2x -4)=0\\\\
\text{Solve: } x^2-2x -4=0\\\\
x_{12}= \frac{-b\pm \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm \sqrt{4+16}}{2}=\frac{2\pm \sqrt{20}}{2}=\frac{2\pm 2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\
x_1 =1+\sqrt{5}\\
x_2 =1-\sqrt{5}\\
\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}$

7 0

2 years ago

Write 3^-4 as a fraction

Ad libitum [116K]

Answer: 1/3^4 or 1 over 3 fourths beacuse you need to just flip it to get the exponent to be positive. 3^-4 is basically 3^-4 over 1.

Step-by-step explanation:

4 0

2 years ago

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How tall is a building that casts a 78-ft shadow when the angle of elevation of the sun is 30 degrees?

Marta_Voda [28]

Answer: $45.03\ ft$

Step-by-step explanation:

Given

The length of the shadow is 78 ft

the angle of elevation is $\theta =30^{\circ}$

Suppose the height of the building is $h$

From the figure, we can write

$\tan 30^{\circ}=\dfrac{h}{78}\\\\h=78\tan 30^{\circ}\\\\h=45.03\ ft$

The height of the building is 45.03 ft

8 0

1 year ago