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3 years ago

For the quadratic equation, state the axis of symmetry, vertex, and any intercepts.

Mathematics

1 answer:

dusya [7]3 years ago

3 0

Answer:

Axis of Symmetry is x = 2

Vertex is (2, -9)

X Intercepts are (5, 0) and (-1, 0)

Step-by-step explanation:

Quadratic Equation is in standard form. Formula find the x value of the vertex in standard form is -b/2a

a=1

b=-4

c=-5

--4/2(1) = 2

Plugin to find the y value of the vertex.

2^2-4(2)-5=y

4-8-5=y

y = -9

The x value of the vertex (in this case is 2) is the axis of symmetry. Therefore the axis of symmetry is x=2

Factor the equation to put into intercept form.

(x-5)(x+1) = y

The equation can be FOIL-ed to get back to standard form.

Separate the 2 parentheses and whatever can cancel the parentheses are your intercepts.

For (x-5) your intercept is (5, 0)

For (x+1) your intercept is (-1, 0)

The x intercepts are where the parabola will cross the x axis on the graph.

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Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures $(6x+20)^{\circ}$ and $(x+100)^{\circ}$ are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

$6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16$

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19. The diagram shows two complementary angles with measures $2x^{\circ}$ and $56^{\circ}$ . The measures of complementary angles add up to $90^{\circ},$ then

$2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17$

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