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pashok25 [27]
3 years ago
5

Can someone like an ace or very good at math help me

Mathematics
1 answer:
eimsori [14]3 years ago
4 0
Supplementary angles , when added, = 180
complimentary angles, when added, = 90

< AQC + < GQC = 180.....supplementary
< BQD + < DQE = 90.......complimentary
< CQE + < EQF = 90.......complimentary
< GQF , < FQE.....neither
< BQC + < DQC = 90....complimentary

< W and < X are supplementary...
if < W = 37, then < X = (180 - 37) = 143

< S and < T are complimentary
if < S = 64, then < T = (90 - 64) = 26

< C and < D are supplementary
if < C = 83, the < D = (180 - 83) = 97

cant read all of the last one.....but if they are complimentary, and 
< U = 41, then the other angle is : (90 - 41) = 49


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Help it's timed.
densk [106]

98 - x² = 0

x² = 98

x = ±√98

Lets factor 98

98 | 2

49 | 7

7 | 7

1

So, 98 = 2 . 7 . 7 = 2 . 7²

x = ±√2.7²

x = ±7√2

4 0
2 years ago
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Find the explicit formula for the given sequence.
Art [367]

Answer:

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2 years ago
. Find two consecutive odd integers whose product is 99. (Note: There are two different pairs of consecutive odd
Tom [10]

Answer:

9 and 11

Step-by-step explanation:Let the 2 consecutive odd integers be n and n+2.

n(n + 2) = 99

Solve for n.

n2 + 2n - 99 = 0

(n + 11)(n - 9) = 0 ⇒

Two solutions:

n = -11

n + 2 = -9

and

n = 9

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Test the answers.

4 0
3 years ago
What is 1/10 of 253 thousandths
Kobotan [32]
1/10×253/1000= 0.0253
5 0
2 years ago
Given: EL- tangent, EK- secant <br> Prove: EJ·LK = EL·LJ
drek231 [11]

Answer:

This is possible.

Step-by-step explanation:

We can say that m<E=m<E, because of the Reflexive Property

Then, we have angles JKL and ELJ, which are equal through the peripheral angle theorem.

With these two angles, we can say that triangles ELK and EJL are similar, by the Angle-Angle Postulate (AA).

Then we can create this ratio through the Corresponding Parts of Similar Triangles Theorem, (CPST), \frac{LK}{LJ} =\frac{EL}{EJ}.

With this ratio, we can cross multiply to get the desired result

EJ·LK=EL·LJ

Hope this helps with your RSM problem

Yup, i caught ya.

3 0
3 years ago
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