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pashok25 [27]
4 years ago
5

Can someone like an ace or very good at math help me

Mathematics
1 answer:
eimsori [14]4 years ago
4 0
Supplementary angles , when added, = 180
complimentary angles, when added, = 90

< AQC + < GQC = 180.....supplementary
< BQD + < DQE = 90.......complimentary
< CQE + < EQF = 90.......complimentary
< GQF , < FQE.....neither
< BQC + < DQC = 90....complimentary

< W and < X are supplementary...
if < W = 37, then < X = (180 - 37) = 143

< S and < T are complimentary
if < S = 64, then < T = (90 - 64) = 26

< C and < D are supplementary
if < C = 83, the < D = (180 - 83) = 97

cant read all of the last one.....but if they are complimentary, and 
< U = 41, then the other angle is : (90 - 41) = 49


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4. The reference angle for 190 is<br> A. 10°<br> B. 180°<br> C. -10°<br> D. 90°
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Answer: A

Step-by-step explanation:  A reference angle is smallest possible angles that  terminal side makes with the x- axis. Since 190 degrees is located i the 3rd quadrant we use the formula 190-180 to find the possible answer and in this case it is A, 10.

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3 years ago
The table below shows the cost of downloading songs from a website. Number of Songs Total Cost 14 $8.96 16 $10.24 18 $11.52 If c
shepuryov [24]

Given:

c = total cost.

s = number of songs.

To solve this question, follow the steps below.

Step 01: Find 2 points (s, c).

You can choose 2 points from the table.

Let's choose (14, 8.96) and (16, 10.24).

Step 02: Substitute one point in the general equation.

Given the general equation:

c=ms+b

Substituting the first point.

\begin{gathered} 8.96=14m+b \\ 8.96-14m=b \\ b=8.96-14m \end{gathered}

Isolating b by subtracting 8.96 m from both sides:

\begin{gathered} 14-8.96m=8.96m+b-8.96m \\ 14-8.96m=b \\ b=14-8.96m \end{gathered}

Step 03: Substitute b in the general equation.

\begin{gathered} c=ms+b \\ c=ms+8.96-14m \end{gathered}

Step 04: Substitute the second point in the equation above.

\begin{gathered} c=ms+8.96-14m \\ 10.24=16m+8.96-14m \\ 10.24=2m+8.96 \end{gathered}

Step 05: Solve the equation above for m.

To do it, first, subtract 8.96 from both sides.

\begin{gathered} 10.24-8.96=2m+8.96-8.96 \\ 1.28=2m \end{gathered}

Now, divide both sides by 2.

\begin{gathered} \frac{1.28}{2}=\frac{2}{2}m \\ m=0.64 \end{gathered}

Step 06: Substitute m in the equation from step 02 to find b.

\begin{gathered} b=8.96-14m \\ b=8.96-14\cdot0.64 \\ b=8.96-8.96 \\ b=0 \end{gathered}

Step 07: Write the equation.

\begin{gathered} c=0.64s+0 \\ c=0.64s \end{gathered}

Answer:

c = 0.64s

7 0
1 year ago
Acellus
navik [9.2K]

Answer:

ASA

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AD= EC             { GIVEN}

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Answer:

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The moon's gravity is about 1/6 that of Earth, so a 9-lb cat would weigh about 9/6 = 1.5 pounds on the moon.

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