Question

Experiments on learning in animals sometimes measure how long it takes mice to find their way through a maze. The mean time is 18 seconds for one particular maze. A researcher thinks that a loud noise will cause the mice to complete the maze faster. She measures how long each of 10 mice takes with a noise as stimulus. The sample mean is x = 16.5 seconds.The alternative hypothesis for the significance test is ________.a. $H_a$:μ≠18b. $H_a$:μ=16.5.c. $H_a$:μ<18.

Answer 1

Answer:

Option c) $H_a:\mu$ is correct

The alternate hypothesis for the significance test is $H_a:\mu$

Step-by-step explanation:

The alternate hypothesis use the sumbol for the population value

Let p be the proportion , Mean be $\mu$ and stadard deviation be $\sigma$

The null hypothesis states that population value is equal to the value mentioned in the given claim.

$H_0:\mu=18$ (by given).

The alternate hypothesis for the significance test states that the opposite of the null hypothesis(based on the claim )

∴ $H_a:\mu$

The symbol "<" because we want to test if the maze is completed faster and thus if the time has decreased.

∴ option c) $H_a:\mu$ is correct.