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mylen [45]
3 years ago
10

Please help with two and four

Mathematics
1 answer:
bagirrra123 [75]3 years ago
4 0
Question 1)
575 = 100%
57.5= 10%
57.5 × 2= 115 (20%)

question 2)
575=100%
57.5=10%
115=20%
5.75=1%.

5.75 × 4=22.8 (4%)

22.8 (4%) + 115 (20%) =137.8(24%) which would be rounded up to 138

hope this helps♡♡~~Chyna
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Answer:

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Step-by-step explanation:

It usually works to follow directions.

a) Substitute the numbers into the formula:

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Find the area of the composite figure.
Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

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<u>To Find :</u>

The Area of the composite figure

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Firstly we need to find the area of Rectangular part.

So We know that,

\boxed{ \rm \: Area  \:  of \:  Rectangle = Length×Breadth}

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

\boxed{\rm \: Breadth = total  \: distance - Radius}

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

\longrightarrow\rm \: Length \:  of \:  the  \: circle = Radius

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Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

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\longrightarrow\rm \: Breadth = 14-6

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Hence, the Breadth is 8 in.

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\longrightarrow\rm \: Area \:  of  \: Rectangle = 6 \times 8

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Then, We need to find the area of Quarter circle :

We know that,

\boxed{\rm Area_{(Quarter \; Circle) }  = \cfrac{\pi{r} {}^{2} }{4}}

Now Substitute their values:

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\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 6 {}^{2} }{4}

Solve it.

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 36}{4}

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}

\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9

\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \:  {in}^{2}

Now we can Find out the total Area of composite figure:

We know that,

\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}

So Substitute their values:

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\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26

Solve it.

\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

\rule{225pt}{2pt}

I hope this helps!

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