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SCORPION-xisa [38]
3 years ago
8

What is the equation of this line? a. y= -2

Mathematics
1 answer:
jeyben [28]3 years ago
5 0
The answer is y = 2x







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Assume V and W are​ finite-dimensional vector spaces and T is a linear transformation from V to​ W, T: Upper V right arrow Upper
scZoUnD [109]

Answer:

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

Step-by-step explanation:

Let B = {v_1 ,v_2,..., v_p} be a basis of H, that is dim H = p and for any v ∈ H there are scalars c_1 , c_2, c_p, such that v = c_1*v_1 + c_2*v_2 +....+ C_p*V_p It follows that  

T(v) = T(c_1*v_1 + c_2v_2 + ••• + c_pV_p) = c_1T(v_1) +c_2T(v_2) + c_pT(v_p)

so T(H) is spanned by p vectors T(v_1),T(v_2), T(v_p). It is enough to prove that these vectors are linearly independent. It will imply that the vectors form a basis of T(H), and thus dim T(H) = p = dim H.  

Assume in contrary that T(v_1 ), T(v_2), T(v_p) are linearly dependent, that is there are scalars c_1, c_2, c_p not all zeros, such that  

c_1T(v_1) + c_2T(v_2) +.... + c_pT(v_p) = 0

T(c_1v_1) + T(c_2v_2) +.... + T(c_pv_p) = 0

T(c_1v_1+ c_2v_2 ... c_pv_p) = 0  

But also T(0) = 0 and since T is one-to-one, it follows that c_1v_1 + c_2v_2 +.... + c_pv_p = O.

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

8 0
3 years ago
the distance around a circle (the circumference) is about 3.14 times the diameter. If a circulares table has a diameter of 3 fee
Katyanochek1 [597]
Well.
The relation between the circumference of a circle and its diameter is described by the following equation: Thecircumference=\pi d
where d is the diameter of the circle.
For a giving diameter (d=3ft), we can substitute in the previous equation 
The circumference of a circule= 3.14*3 (you can use ur calculator to find the exact number i guess it will be about 9.42 ft)

I hope it helps.
8 0
3 years ago
Show work on how to do it
svetlana [45]

Answer:

3 steps rotations

Step-by-step explanation:di ko sigurado

7 0
2 years ago
Helppppppppppp please...
Ede4ka [16]
Order from left to right by row
2
3
80
1
-40
1/6
240
3 0
3 years ago
Help plsssssssssssss
sammy [17]

Answer:

\frac{x {y}^{ - 1} }{2 {x}^{0}{y}^{ - 2} }  \\  =  \frac{x {y}^{2} }{2 \times 1 \times y}  \\  =  \frac{x {y}^{2} }{2y}  \\  =  \frac{xy}{2}

<h3>(xy)/2 is the right answer.</h3>
8 0
3 years ago
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