Answer:
After 90° rotation,
(x,y) ----> (y,-x)
A (-7, 4) ----> A' (4,7)
B (-7, 1 ) ----> B' (1,7)
C (-2 ,1) ----> C' (1,2)
D (-2,4) ----> D' (4,2)


<u> </u><u> </u><u> </u><u>–</u><u>3</u><u> </u><u> </u><u> </u><u>×</u><u> </u><u> </u><u> </u><u>–</u><u>4</u><u> </u><u> </u><u> </u><u> </u><u> </u>
10


<h3>HOPE THIS HELPS :)</h3>
Answer:
A
Step-by-step explanation:
There is an outlier of a sign with a speed limit of 10 miles per hour.
tangent is less than 0 or tan(θ) < 0, is another way to say tan(θ) is negative, well, that only happens on the II Quadrant and IV Quadrant, where sine and cosine are different signs, so we know θ is on the II or IV Quadrant.

![\bf \pm\sqrt{3^2-2^2}=a\implies \pm\sqrt{5}=a\implies \stackrel{\textit{II Quadrant}}{-\sqrt{5}=a} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{-\sqrt{5}}}{\stackrel{hypotenuse}{3}}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cpm%5Csqrt%7B3%5E2-2%5E2%7D%3Da%5Cimplies%20%5Cpm%5Csqrt%7B5%7D%3Da%5Cimplies%20%5Cstackrel%7B%5Ctextit%7BII%20Quadrant%7D%7D%7B-%5Csqrt%7B5%7D%3Da%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20cos%28%5Ctheta%20%29%3D%5Ccfrac%7B%5Cstackrel%7Badjacent%7D%7B-%5Csqrt%7B5%7D%7D%7D%7B%5Cstackrel%7Bhypotenuse%7D%7B3%7D%7D~%5Chfill)
Step-by-step explanation:
Distance Chase thought he travelled = 40 feet
The actual distance travelled by him = 32 feet
Error % = (40 - 32)/ 100
= 8/100
= 0.08