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slava [35]
3 years ago
9

-3/10x (-0.1) can you please help ASAP

Mathematics
1 answer:
Gre4nikov [31]3 years ago
8 0

\frac{ - 3}{10}  \times ( - 0.1)

\frac{ - 3}{10}  \times  \frac{ - 1}{10}

<u> </u><u> </u><u> </u><u>–</u><u>3</u><u> </u><u> </u><u> </u><u>×</u><u> </u><u> </u><u> </u><u>–</u><u>4</u><u> </u><u> </u><u> </u><u> </u><u> </u>

10

\frac{12}{10}

\frac{6}{5} answer

<h3>HOPE THIS HELPS :)</h3>
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Answer:

D. sum of these edges is increased by 24 inches -- True

Step-by-step explanation:

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To study the effect of this increase in the Volume, area of each face, diagonal and sum of edges.

Solution:

Let the side of original cube = a inches.

Formula for volume of cube:

V =side^3 = a^3

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(x+y)^3 =x^3+y^3+3xy(x+y)

V' = (a+2)^3 = a^3+8+3\times 2 \times a(a+2)=a^3+8+6a(a+2)

So, V' = V + 8+6a(a+2)

Volume increased by 8+6a(a+2) [which is not equal to 8]

So, statement is false:

A. volume is increased by 8 cubic inches  -- False

Each face in a cube is a square.

Area of each face, A = side^2 = a^2

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Using the formula: (x+y)^2 =x^2+y^2+2xy

A' = a^2+4+4a

Area increased by 4+4a [which is not equal to 4 sq inches]

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So, increase of 2\sqrt2 not 2.

C. diagonals of each face is increased by 2 inches -- False

There are 12 number of edges in a square.

So sum of all 12 edges  = 12a

When edge is increased by 2, sum of all edges = 12(a+2) = 12a + <em>24</em>

An increase of 24.

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Answer:

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