Let A represent the speed of car A. Using your formula,
.. A*2 = D
.. (A +15)*1.5 = D . . . . . the same distance in a shorter time at a higher speed
Equating the two expressions for D, we get
.. 2A = 1.5(A +15)
.. 2A = 1.5A +22.5 . . . . . eliminate parentheses
.. 0.5A = 22.5 . . . . . . . . .subtract 1.5A
.. A = 22.5/0.5 = 45 . . . .divide by 0.5
Car B was 15 mph faster than this.
Car B traveled at 60 miles per hour.
Answer:
that one over there
Step-by-step explanation:
Given:
12 inches in 1 foot
number of inches in 2.5 feet
2.5 feet * 12 inches/1foot = 2.5 * 12 inches = 30 inches
1 foot + 1 foot + 0.5 foot = 2.5 feet
12 inches + 12 inches + 6 inches = 30 inches
12 inches : 1 foot = x : 2.5 feet
12 inches * 2.5 feet = x*1foot
30 inches * feet = x * foot
30 inches = x
Answer:
12.6
Step-by-step explanation:
Given the function, F(x)=20/4+3e−0.2x
Where e is an exponential function,
To get f(3), we need to substitute x = 3 into the given function
F(3) = 20/4 + 3e - 0.2(3)
f(3) = 5 + 3e - 0.6
f(3) = 4.4+3e
Substituting the value of e = 2.718
f(3) = 4.4+3(2.718)
f(3) = 12.554
f(3) = 12.6 to the nearest tenth.
