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Rufina [12.5K]
3 years ago
6

How do you get 99 points on sunny meadows simulation?

Computers and Technology
2 answers:
SCORPION-xisa [38]3 years ago
5 0
<span>having: 80 foxes, 8,500 rabbits, and 110,000 plants is for 98 points, I cannot configure 99 points.</span>
satela [25.4K]3 years ago
5 0

Answer:

having everything

Explanation:

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star wars death star....

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At the data science laboratory, the data scientists and data engineers are required to process millions of data every second to
defon

Answer:

the type of computer system that is required for processing of scientific data is : supercomputer

for distribution of data over a network :Client/server computing

working from home :A laptop

3 0
3 years ago
To view the contents of a file that was compressed with the bzip2 utility, you must used the ____________________ command.
bekas [8.4K]

Answer:

zcat

Explanation:

Zcat is a command line utility for viewing the contents of a compressed file without literally uncompressing it. It expands a compressed file to standard output allowing you to have a look at its contents. In addition, zcat is identical to running gunzip -c command.

8 0
4 years ago
Write an application that displays every perfect number from 1 through 1,000. A perfect number is one that equals the sum of all
matrenka [14]

Answer:

Written in Python

for num in range(1,1001):

    sum=0

    for j in range(1,num+1):

         if num%j==0:

              sum = sum + j

                   if num == sum:

                        print(str(num)+" is a perfect number")

Explanation:

This line gets the range from 1 to 1000

for num in range(1,1001):

This line initializes sum to 0 for each number 1 to 1000

    sum=0

This line gets the divisor for each number 1 to 1000

    for j in range(1,num+1):

This following if condition line checks for divisor of each number

<em>          if num%j==0: </em>

<em>               sum = sum + j </em>

The following if condition checks for perfect number

                   if num == sum:

                        print(str(num)+" is a perfect number")

5 0
3 years ago
This program is to compute and write to a file the GPA for student scores read from an input file. The point values of the grade
VARVARA [1.3K]

Answer:

#Take input from the user

filename=input('Enter name of input file: ')

total_units=0#Total number of units for a student

total_score=0#Total score of a student

#Assign a score to each grade. I have reduced 0.33 for each grade. Change here if you need to

grade={'A':4.0,'A-':3.67,'B+':3.34,'B':3.01,'B-':2.68,'C+':2.35,'C':2.02,'C-':1.69,'D+':1.36,'D':1.03}

try:

with open(filename,"r") as input_file:#Open the file for input(reading)

output_file=open("GPA_output.txt","w") #Create and open GPA_output.txt if it doesn't exist for writing

for student_record in input_file:#read from input file

if("," in student_record):#if there is a , that means this is the student name

student_name=student_record.strip('\n')#Remove \n from student name

continue

else:

if(" " in student_record):#If a line contains spaces then its the student's grades for a course

student=student_record.split(" ")#Split to find the coursename, units and grade

#student[0]=coursename student[1]=units student[2]=grade

total_units+=int(student[1])#Calculate total units for 1 student

total_score+=int(student[1])*grade[student[2].strip('\n')]#Find the total score of a student

#grade[student[2]] will lookup for the score that we initialized earlier

#if student has a grade as A then this will look up as grade['A'] which will return 4

#Find the total score as product of this grade and units for this course

continue

else:

if(total_units>0):#Check if score has been calculated for a student earlier

print("in")

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

if(total_units>0):#Essential for the case when the file doesn't end with a new line(Check if total_units is not 0) which means a record is pending

#to be written to the file

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

input_file.close()#Close the input file

output_file.close()#Close the output file

except IOError as e:

print("Problem in Opening the required file")#Print a message if file cannot be opened

Explanation:

The program has been tested for all 3 scenarios mentioned i.e.

a. If the file ends without \n

b. If the file ends with 2 \n

c. If the file ends with 1 \n

PS: The Program will run irrespective of how it ends. Even if there are many \n at the end of file, the program will be fine.

3 0
3 years ago
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