Answer: Laser Beams
Explanation:
The laser beam is one of the type of technology that helps in amplifying the light by using the laser principle Stimulated emission in the laser. The word "LASER" is stand for the Light amplification by stimulated emission of radiation.
The laser is one of the device that emitted the coherent light in the form of beam rays that is propagate only in one direction. The following are the laser beam technology are as follows:
- Bar code reader
- Laser surface modification
- Information processing
- Laser range
Therefore, Laser beam is the correct answer.
Answer: (A) Internet connectivity and bandwidth
Explanation:
The internet connectivity and the bandwidth are the two main factors that are required to play an essential role for accessing the various web apps.
A web application are easily accessible by the internet by means of the web, so availability and transfer speed assume the most significant job in how accessing the application for the client.
By using high internet connectivity, it provide high accessibility to web app for accessing different type of services in the system. It also required high bandwidth for providing the easy accessibility to the web app.
D that is the answer but I need 20 words to send this text
Answer:
A) 2.56 ms
B) 128 μs
Explanation:
Time for Bus cycles = 500 ns
Transfer of bus control = 250 ns
I/0 device data transfer rate = 50 KB/s
Data are transferred at : 1 byte at a time
A) Determine how long the device tie up the bus when transferring a block of 128 bytes
Block size to be transferred = 128 bytes
Bandwidth = 50 KB/s
data transfer = (Block size ) / ( Bandwidth)
= ( 128 * 8 ) / ( 50 * 10^3 * 8 )
= ( 1024 ) / ( 50 * 10^3 * 8 )
= 2.56 ms
To determine the actual transfer time we have to add up the transfer time for the bus control in both directions :
2.56 ms + 500 ns = 2.56 ms. this is because 500 ns is not a significant value
B) cycle stealing mode
In this mode each byte is transferred at a time and The total transfer time needed for the bus control in both directions will be double the total time i.e 2 * 500 ns = 1000 ns. because additional control time of 250 ns is required at both ends
since 1 byte is transferred at a time , 1 byte will be transferred in 1 μs
128 bytes = 128 * 1 μs = 128 μs