Answer:
if(isBalloon== true && isRed==false) //compare the value of isBalloon variable with true value and isRed variable value with false value.
System.out.println("Balloon");//Print Balloon
else if(isBalloon== true && isRed==true) //compare the value of isBalloon variable with true value and isRed variable value with also true value.
System.out.println("Red balloon");//Print Red Balloon
else // when no if condition match it will execute.
System.out.println("Not a balloon"); //Print Not a Balloon
Output:
Not a balloon
Explanation:
The "if-else" statement is defined above for the problem which is given on the question. The detailed explanation of the answer is described below--
- Firstly we need to check the "true" value for the "isBalloon" variable and "false" value for "isRed" variable. This is done in "if" statement separated with and(&&) operator which gives "true" when both are the true statement.
- Then we need to check the "true" value for the "isBalloon" variable and "isRed" variable. For this, we need to use "else if" statement which executes when "if" statement is false.
- Then we need to print the "Not a balloon" statement if both cases are false, for this, we use "else" statement which executes when the "if" and "else if" statement are false.
Answer:.I used to play it but now I don’t;—;
Explanation:
Answer: No
Explanation:
For the same reason that two people cannot have the same address, it's just a virtual address.
Turn on your Xbox One and go to the Settings menu.
Select Network.
Select Set Up wireless network, to connect to a new network.
Xbox One asks Which one is yours? and displays the wireless networks it detects in your area.
Select the network you want to connect to.
