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mestny [16]
3 years ago
15

What is 1/5 and a coin name

Mathematics
1 answer:
yulyashka [42]3 years ago
8 0
If you speak of money, 1/5 would be 20 cents. To get 20 cents, there is a few different coins that can come up with it.

Penny - 1 + 1 + 1 + 1 + 1 1 + 1 + 1 + 1 + 1 1 + 1 + 1 + 1 + 1 1 + 1 + 1 + 1 + 1 (This is 20 ones.)

Nickel - 5 + 5 + 5 +5

Dime - 10 + 10

I hope this answer cleared up any confusion you may have been having, feel free to comment on my profile or PM me if you need further assistance. :)

- Sofie
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Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention
Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

a=\frac{d^2s}{dt^2}

Differentiate the position vector with respect to t.

\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}

Differentiate both sides of the obtained equation with respect to t.

\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.

\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}

The initial position is obtained at t=0. Substitute t=0 in the given position function.

\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}

8 0
1 year ago
ASAP pls helppppppppppppppppp!!!
Sunny_sXe [5.5K]

The answer is 7.

Look at the x=8 and then look up the y-value.

The graph passes (8,7) so therefore when x = 8 the y is 7

4 0
2 years ago
-21 = 7(3 - x)<br><br> Please help. You have to use distributive property to solve.
OlgaM077 [116]
The answer is 6


hope this helps !!
4 0
3 years ago
Read 2 more answers
A boundary stripe 6 in. wide is painted around a rectangle whose dimensions are 120 ft by 230 ft. Use differentials to approxima
Nimfa-mama [501]

Answer:

350 square feet

Step-by-step explanation:

We are given that

Width of strip=6 in

Dimension of rectangle=20 ft\times 230 ft

We know that

Area  of rectangle ,A=xy

Differentiate

dA=\frac{\partial A}{\partial x}x+\frac{\partial A}{\partial y}y

We have \frac{\partial A}{\partial x}=y=230 ft

\frac{\partial A}{\partial y}=x=120

dx=\frac{12}{12}=1 ft

1 ft=12 in

Because 6 in added in both side of breadth

dy=\frac{12}{12}=1 ft

Because 6 in added on both sides of length of rectangle

Substitute the values

dA=230\times 1+120\times 1=350 ft^2

Hence, the number of square feet of paint in the strip=350 square feet

7 0
3 years ago
Look at abc. which triangle is congruent abc by the asa criterion
Bad White [126]
There is only 1 triangle
4 0
3 years ago
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