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3 years ago

A bobsled’s distance-time graph indicates that it traveled 100 m in 25 s. What is the bobsled’s speed?

2 answers:

8 0

Its AVERAGE speed for the whole 25s was (100m/25s)= 4 m/s.

It may have been faster or slower than that at different times during the 25s. You'd have to see the graph to know what it was at any particular instant.

vfiekz [6]3 years ago

7 0

Speed is defined as distance over time. So, since it traveled 100m in 25 sec, the speed was 100 / 25 = 4 m/s.

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<h2>Right answer: 64 units</h2><h2></h2>

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$F=G\frac{m_{1}m_{2}}{r^2}$

Where:

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$G$ is the universal gravitation constant.

$m_{1}$ and $m_{2}$ are the masses of both bodies.

$r$ is the distance between both bodies

In this case we have a gravitation force $F_{1}=16units$ , given by the formula written at the beginning. Let’s rename the distance $r$ as $d$ :

$F_{1}=G\frac{m_{1}m_{2}}{d^2}$ (1)

And we are asked to find the gravitation force $F_{2}$ with a given distance of $\frac{d}{2}$ :

$F_{2}=G\frac{m_{1}m_{2}}{({\frac{d}{2})}^{2}}$

$F_{2}=G\frac{m_{1}m_{2}}{{\frac{d^{2}}{4}}}$ (2)

The gravity constant is the same for both equations, and we are assuming both masses are constants, as well. So, let’s isolate $G m_{1}m_{2}$ in both equations:

From (1):

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If (3)=(4):

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$F_{2}=F_{1}{d}^{2}\frac{4}{{d}^{2}}$

$F_{2}=4F_{1}$ (6)

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$F_{2}=(4)(16 units)$

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