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3 years ago

If you're not satisfied with your fitness evaluation score, there's really little you can do about it.

Physics

3 answers:

Doss [256]3 years ago

4 0

Answer:

false

Explanation:

you can improve your score next time

BARSIC [14]3 years ago

3 0

Answer:

False

Explanation:

Alizaha2 years ago

0 0

Answer:False :>

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A long, thin superconducting wire carrying a 17 A current passes through the center of a thin, 3.0-cm-diameter ring. A uniform e

nalin [4]

Answer:

$\frac{dE}{dt} =- 2.72 *10^{15} \ N/C \cdot s$

The direction of the electric field is opposite that of the current

Explanation:

From the question we are told that

The current is $I = 17\ A$

The diameter of the ring is $d = 3.0 \ cm = 0.03 \ m$

Generally the radius is mathematically represented as

$r = \frac{d}{2}$

$r = \frac{0.03}{2}$

$r = 0.015 \ m$

The cross-sectional area is mathematically represented as

$A = \pi r^2$

=> $A = 3.142 * (0.015^2)$

=> $A = 7.07 *10^{-4 } \ m^ 2$

Generally according to ampere -Maxwell equation we have that

$\oint \= B \cdot \= ds = \mu_o I + \epsilon_o \mu _o\frac{ d \phi }{dt }$

Now given that $\= B = 0$ it implies that

$\oint \= B \cdot \= ds = 0$

$\mu_o I + \epsilon_o \mu _o\frac{ d \phi }{dt } = 0$

Where $\epsilon _o$ is the permittivity of free space with value $\epsilon_o = 8.85*10^{-12 } \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2$

$\mu_o$ is the permeability of free space with value

$\mu_o = 4\pi * 10^{-7} N/A^2$

$\phi$ is magnetic flux which is mathematically represented as

$\phi = E * A$

Where E is the electric field strength

$\mu_o I + \epsilon_o \mu _o \frac{ d [EA] }{dt } = 0$

=> $\frac{dE}{dt} =- \frac{I}{\epsilon_o * A }$

=> $\frac{dE}{dt} =- \frac{17}{8.85*10^{-12} * 7.07*10^{-4} }$

=> $\frac{dE}{dt} =- 2.72 *10^{15} \ N/C \cdot s$

The negative sign shows that the direction of the electric field is opposite that of the current

8 0

3 years ago

Challenge Question (This is supposed to be hard, think critically and take it one step at a time):

aivan3 [116]

Answer:

You must travel at an average speed of 67.06 m/s to be on time to the lecture.

Explanation:

From the question, the total distance from your house to the science lecture is 75 miles.

Also, you get halfway there before you stop for a gas, that is, you have covered half of 75 miles, which 37.5 miles and you also have to cover 37.5 miles to get to the science lecture.

After filling up, you only have 15 minutes before the lecture starts,

To determine how fast you must drive to be on time to the lecture,

we will determine the average speed you need to travel.

From

Average speed = Distance / Time

Distance = 37.5 miles (Convert to meters)

(NOTE: 1 mile = 1609.344 meters)

Hence, 37.5 miles = 37.5 × 1609.344 miles = 60350.4 meters

∴ Distance = 60350.4 meters

Time = 15 minutes (Convert to seconds)

(NOTE: 1 minute = 60 seconds)

Hence, 15 minutes = 15 × 60 seconds = 900 seconds

Now, from

Average speed = Distance / Time

Average speed = 60350.4 m / 900 s

Average speed = 67.06 m/s

Hence, you must travel at an average speed of 67.06 m/s to be on time to the lecture.

8 0

4 years ago

An object moves with a velocity that changes. •1st law •2nd law

Triss [41]

Answer:

2ed law

Explanation:

i just looked it hope it helps

6 0

3 years ago

Read 2 more answers

A 17 N box is carried across the room a distance of 9.1 m. How much work was performed?

Rainbow [258]

Answer:

D: 154.7 J

Explanation:

Using the formula for work, the formula is

Force(Newtons) x Distance(Meters)

therefore, 17 x 9.1

and it will be 154.7 Joules: D

3 0

3 years ago

The diagram shows three vectors.

AlexFokin [52]

Any vector which is made in x-y plane will have some angle with the x axis

in that case we can say that

$P_X = P cos\theta$

also for Y direction we can say

$P_y = P sin\theta$

so here the two components of vector is given by Px and Py

so we can say that

$\vec P = (Pcos\theta)\hat i + (Psin\theta)\hat j$

so correct answer would be

Vectors Px and Py are components of vector P.

7 0

3 years ago