Products must equal which in a chemical reaction?

On a spending spree in Malaysia, you buy an ox with a weight of 28.9 piculs in the local unit of weights: 1 picul = 100 gins, 1

Talja [164]

Answer:

1747.41 kg

Explanation:

If 1 piculs = 100 gins,

Then 28.9 piculs = (28.9 × 100) gins = 2890 gins.

Also,

If 1 gin = 16 tahils

then 2890 gins =( 16 × 2890 ) = 46240 tahils

Also,

If 1 tahil = 10 chees,

Then 46240 tahils = 46240 × 10 chees = 462400 chees.

Also,

If 1 chee = 10 hoons

Then 462400 chees =( 10 × 462400) hoons = 4624000 hoons.

Also,

If 1 hoon = 0.3779 g,

Then 4624000 hoons = 0.3779 × 4624000 = 1747409.6 g.

The mass in kg that i will declare in the shipping manifest = (1747409.6/100 )kg = 1747.41 kg

6 0

3 years ago

The terminal velocity of a sand grain in air is __________ the terminal velocity of the same sand grain in seawater. greater tha

hoa [83]

<span>The terminal velocity of a sand grain in the air is greater than the terminal velocity of the same sand grain in seawater. The terminal velocity is greater in the air because it is less dense compared to a much denser sea water. Terminal velocity takes lace when an object is constantly free-falling.</span>

7 0

4 years ago

The reaction is at dynamic equilibrium.

DiKsa [7]

Answer:

Nitrogen and hydrogen combine at the same rate that ammonia breaks down.

Explanation:

7 0

3 years ago

A grapefruit falls from a tree and hits the ground .75 seconds later. How far did the grapefruit drop? What was its speed?

Ivanshal [37]

1) The grapefruit is in free fall, so it moves by uniformly accelerated motion, with constant acceleration $g=9.81 m/s^2$ . Calling h its height at t=0, the height at time t is given by
$h(t)=h- \frac{1}{2}gt^2$
We are told thatn when $t=0.75 s$ the grapefruit hits the ground, so h(0.75 s)=0. If we substitute these data into the equation, we can find the initial height h of the grapefruit:
$0=h- \frac{1}{2}gt^2$
$h= \frac{1}{2}gt^2= \frac{1}{2}(9.81 m/s^2)(0.75 s)^2=2.76 m$

2) The speed of the grapefruit at time t is given by
$v(t)=v_0 +gt$
where $v_0=0$ is the initial speed of the grapefruit. Substituting t=0.75 s, we find the speed when the grapefruit hits the ground:
$v(0.75 s)=gt=(9.81 m/s^2)(0.75 s)=7.36 m/s$

3 0

4 years ago

When a fixed amount of ideal gas goes through thermal expansion what happens to internal energy

Keith_Richards [23]

Answer:

A) its internal (thermal) energy does not change.

Explanation:

When a fixed amount of ideal gas goes through an isothermal expansion

3 0

3 years ago