Answer:
a) 72.54° and It will take the woman 33.4m
Explanation:
The woman runs with a constant speed V1 = 6m/s
V2 = 20m/s
V1 = V2 cos θ
Cos θ= V1/V2= 6/20
Cos θ= 0.3
Cos^-1 0.3=72.54°
Using Range formular for projectile
R= (V2 Cos θ)/g (V2 Sin θ)^2 +sqrt(V2 Sin θ)^2 + 2gh)
R= (20cos72.54)(2Sin72.54+sqrt(20Sin72.54)^2 + 2×9.8×45
R=33.4m
b )
see the attached file
So, the time that taken for the astronaut to fall to the surface of the moon is <u>2.5 s.</u>
<h3>Introduction</h3>Hi ! In this question, I will help you. In this question, you will learn about the fall time of the free fall motion. Free fall is a downward vertical motion without being preceded by an initial velocity. When moving in free fall, the time required can be calculated by the following equation:
With the following condition :
We know that :
What was asked :
Step by step :
So, the time that taken for the astronaut to fall to the surface of the moon is 2.5 s.
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