Answer:
50%
Step-by-step explanation:
You can literally do it mentally lol
$500,000
- <u>$250,000</u>
$250,000
so by common sense, it's 50%
Hope it helped!
Okay, so first of all, if the trapezoid was translated right 4,
Then all the (x)'s should be 4 more than the original value
For example: (2,-3) <span>→ (6,-3)
Now since the Trapezoid was translated down 3,
Then all the (y)'s should be 3 less than the original value
For example: (2,-3) </span><span>→ (2,-6)
Now do this to all the Vertices
</span>
Final Answer: <span>
Option 2</span>
Answer:
£160
Step-by-step explanation:
£262 x (100% - 39%) = £159.82 ≈ £160
Answer: Arc CE measures 62 units
Step-by-step explanation: What we have in the question is a circle with two secants ABC and ADE. The two secants have been extended such that two arcs have been formed which are, major arc CE (that is, 4x - 10) and minor arc BD (that is 26).
When you have a circle with two intersecting secants, the angle x (that is angle CAE) is derived as half of the difference of the two intercepted arcs. That is;
Angle x = 1/2 [CE - BD)
Angle x = 1/2 [ (4x - 10) - 26]
Angle x = 1/2(4x - 36)
Cross multiply and we now have
2x = 4x - 36
Collect like terms and we now have
36 = 4x - 2x
36 = 2x
Divide both sides by 2
18 = x
Having calculated x as 18, where arc CE equals 4x - 10, then substitute for the value of x.
CE = 4(18) - 10
CE = 72 - 10
CE = 62
Answer:
The significance level is
and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

So we reject the null hypothesis is 
Step-by-step explanation:
For this case we define the random variable X as the number of entry-level swimmers and we are interested about the true population mean for this variable . On specific we want to test this:
Null hypothesis: 
Alternative hypothesis: 
And the statistic is given by:

The significance level is
and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

So we reject the null hypothesis is 