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patriot [66]
3 years ago
5

A length of rope is stretched between the top edge of a building and a stake in the ground. The head of the stake is at ground l

evel. The rope also touches a tree that is growing halfway between the stake and the building. If the the building is 36 feet tall, how tall is the tree?

Mathematics
2 answers:
ss7ja [257]3 years ago
8 0

Answer:

The correct answer would be:

Step-by-step explanation:

18ft

4vir4ik [10]3 years ago
6 0
X - height of the tree.
A proportion is:
1/2  : x = 1 : 36
x = 36 * 1/2
x = 18
Answer. the tree is 18 feet tall.
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Answer:

\boxed{c = -17}

Step-by-step explanation:

=  > 3 - 7c - 20c = 7( - 7c - 19) + 14c \\  \\  =  > 3 - 27c = ( - 7c \times 7) - (7 \times 19) + 14c \\  \\  =  > 3 - 27c =  - 49c - 133 + 14c \\  \\  =  > 3 - 27c =  - 35c - 133 \\  \\  =  > 3 - 27c + 35c =  - 133 \\  \\  =  > 3  + 8c =  - 133 \\  \\  =  > 8c =  - 133 - 3 \\  \\  =  > 8c =  - 136 \\  \\  =  > c =  -  \frac{136}{8}  \\  \\  =  > c =  - 17

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maria [59]

Answer:

First option:  3x^2-5x=-8

Second option: 2x^2=6x-5

Fourth option: -x^2-10x=34

Step-by-step explanation:

Rewrite each equation in the form ax^2+bx+c=0 and then use the Discriminant formula for each equation. This is:

D=b^2-4ac

1) For 3x^2-5x=-8:

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Then:

D=(-5)^2-4(3)(8)=-71

Since D this equation has no real solutions, but has two complex solutions.

2) For 2x^2=6x-5:

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Then:

D=(-6)^2-4(2)(5)=-4

Since D this equation has no real solutions, but has two complex solutions.

3) For 12x=9x^2+4:

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Then:

D=(-12)^2-4(9)(4)=0

Since D=0 this equation has one real solution.

4) For -x^2-10x=34:

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Then:

D=(-10)^2-4(-1)(-34)=-36

Since D, this equation has no real solutions, but has two complex solutions.

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