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densk [106]
3 years ago
14

PLEASE HELP ASAP

Mathematics
1 answer:
maria [59]3 years ago
3 0

Answer:

First option:  3x^2-5x=-8

Second option: 2x^2=6x-5

Fourth option: -x^2-10x=34

Step-by-step explanation:

Rewrite each equation in the form ax^2+bx+c=0 and then use the Discriminant formula for each equation. This is:

D=b^2-4ac

1) For 3x^2-5x=-8:

 3x^2-5x+8=0

Then:

D=(-5)^2-4(3)(8)=-71

Since D this equation has no real solutions, but has two complex solutions.

2) For 2x^2=6x-5:

 2x^2-6x+5=0

Then:

D=(-6)^2-4(2)(5)=-4

Since D this equation has no real solutions, but has two complex solutions.

3) For 12x=9x^2+4:

 9x^2-12x+4=0

Then:

D=(-12)^2-4(9)(4)=0

Since D=0 this equation has one real solution.

4) For -x^2-10x=34:

 -x^2-10x-34=0

Then:

D=(-10)^2-4(-1)(-34)=-36

Since D, this equation has no real solutions, but has two complex solutions.

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