<span>To answer this question, the equation that we will be using is:
y = A cos bx + c
where A = amplitude, b = 2 pi/Period, Period = 12 hrs, c = midline,
x = t and y = f(t)
A = 1/2 (Xmax - Xmin)
12 - 2 / 2 = 10/2 = 5
b = 2 pi / 12 = pi/6
c = 1/2 (Xmax + Xmin)
12+2/2 = 7
answer: f(t) = 5 cos pi/6 t + 7 </span>
Answer:
Work, W = F * d, and
Work = change in kinetic energy, so W=deltaKE.
Hence,
deltaKE=F * d
(1/2)*m*v^2 =F * d
d=[(1/2)*m*v^2]/F
d=[(1/2)*0.6*20^2]/5
d=24 m.
Explanation:
Work = change in kinetic energy, so W=deltaKE.
Answer:
231.98 mL
Explanation:
V₁ = Initial volume = 205 mL
V₂ = Final volume
P₁ = Initial pressure = 712 mmHg
P₂ = Final pressure = 750 mmhg (STP)
T₁ = Initial temperature = -44 °C = 229.15 K
T₂ = Final temperature = 273.15 K (STP)
From Combined gas law

Volume of the argon at STP is 231.98 mL
I’m sorry i haven’t found the answer to this
As we know,

so, let's solve for velocity (v)