The magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.
<h3>Impulse experienced by objects</h3>
The impulse experienced by any object is equal to the change in the momentum of the object.
The magnitude of the impulse delivered to the baseball by the bat is calculated by applying the following equation.
J = Ft
where;
- F is applied force = 8000 N
- t is time, = 1.1 ms
J = (8000) x (1.1 x 10⁻³)
J = 8.8 Ns
Thus, the magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.
Learn more about impulse here: brainly.com/question/229647
<span>Velocity, you divide distance/time </span>
Answer:
F = 2.49 x 10⁻⁹ N
Explanation:
The electrostatic force between two charged bodies is given by Colomb's Law:

where,
F = Electrostatic Force = ?
k = colomb's constant = 9 x 10⁹ N.m²/C²
q₁ = charge on proton = 1.6 x 10⁻¹⁹ C
q₂ = second charge = 1.4 C
r = distace between charges = 0.9 m
Therefore,

<u>F = 2.49 x 10⁻⁹ N</u>
Answer:
The focal length of the lens is 34.047 cm
The power of the needed corrective lens is 2.937 diopter.
Explanation:
Distance of the object from the lens,u = 26 cm
Distance of the image from the lens ,v= -110 cm
(Image is forming on the other side of the lens)
Since ,lens of the human eye is converging lens,convex lens.
Using a lens formula:


f = 34.047 cm = 0.3404 m
Power of the lens = P
