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valkas [14]
3 years ago
11

Kira goes running Monday, Wednesday, and Friday of each week. Each Monday she runs 2.5 miles, each Wednesday she runs 5.75 miles

, and each Friday she runs 7.75 miles. How many total miles does she run in 9 weeks
Mathematics
1 answer:
alexira [117]3 years ago
8 0

Kira runs 144 miles in 9 weeks.

Step-by-step explanation:

Given,

Distance ran on Monday = 2.5 miles

Distance ran on Wednesday = 5.75 miles

Distance ran on Friday = 7.75 miles

Distance ran in one week = 2.5+5.75+7.75 = 16 miles

Distance ran in 9 weeks = Number of weeks * Distance ran in one week

Distance ran in 9 weeks = 16*9 = 144 miles

Kira runs 144 miles in 9 weeks.

Keywords: multiplication, addition

Learn more about addition at:

  • brainly.com/question/10894205
  • brainly.com/question/10987396

#LearnwithBrainly

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Explain which number is the "odd ball out" below<br> 42, 9, 60, 8, 12
stiv31 [10]

Answer:

9

Step-by-step explanation:

because its odd    

3 0
3 years ago
Jenny invests $2,000 at an interest rate of 5%. The amount of money, ma, in Jenny's account after t years can be
Margaret [11]

After t years, the expression that can be used to represent the money in Jenny account is  Mp=2000(1.05)^t+(1.05)^4

<h3 /><h3>Compound interest Computation</h3>

Given Data

  • Principal  P = $2000
  • Rate r = 5%
  • Time t = 4 years

A = P + I where

P (principal) = $2,000.00

I (interest) = $431.01

Calculation Steps:

First, convert R as a percent to r as a decimal

r = R/100

r = 5/100

r = 0.05 rate per year,

Then solve the equation for A

A = P(1 + r/n)^nt

A = 2,000.00(1 + 0.05/1)(1)(4)

A = 2,000.00(1 + 0.05)(4)

A = $2,431.01

Summary:

The total amount accrued, principal plus interest, with compound interest on a principal of $2,000.00 at a rate of 5% per year compounded 1 times per year over 4 years is $2,431.01.

Learn more about compound interest here:

brainly.com/question/24924853

7 0
3 years ago
Read 2 more answers
Adam buys a car for £18680 which depreciates in value at a rate of 2.5% per year. Work out how much Adam's car will be worth in
timofeeve [1]

Answer:

Adam's car will be 8,406£ in 22 years.

Step-by-step explanation:

I. Find the lose value of 2.5% car by

2.5/100 = x/18,680

46,700/100 = x

x = 467 or the lose value in 1st year.

II. Find the true value of Adam's car by

n year = 18,680 - 467(n)

1st = 18,680 - 467(1)

    = 18,213 means if he sell his car now, he'll get 18,213£

22th = 18,680 - 467(22)

        = 18,680 - 10,274

        = 8,406£

That makes 8,406£ is the right answer.

Hope that help :)

4 0
3 years ago
Reflecting<br> Which segment is a reflection of segment AB over the line x = 1?
Paul [167]

Answer:     The correct answer is: (Line segment E F)

Step-by-step explanation:  Took the assignment.

8 0
4 years ago
Read 2 more answers
A car was valued at $39,000 in the year 1995. The value depreciated to $11,000 by the year 2003.
denis23 [38]

Answer:

14.6328% , $5836.03

Step-by-step explanation:

Here we are going to use the formula

A_{0}(1-r)^n = A_{n}

A_{0} = 39000

r=?

A_{8} = 11000

n=8

Hence

39000(1-r)^8 = 11000

(1-r)^8 = \frac{11000}{39000}

(1-r)^8 = 0.2820

(1-r) = 0.2820^{\frac{1}{8}

(1-r) = 0.2820^{0.125}

(1-r) = 0.8536

(1-0.8536=r

r = 0.1463

Hence r= 0.1463

In percentage form r = 14.63%

Now let us see calculate the value of car in 2003 that is after 12 years

we use the main formula again

A_{0}(1-r)^n = A_{n}

A_{0} = 39000

r=0.1463

A_{12} = ?

n=12

39000(1-0.14634)^{(12} = A_{12}

39000(0.8536)^{12} = A_{12}

39000*0.1497 = A_{12}

A_{12}=5840.34

Hence the car's value will be depreciated to $5840.34 (approx) by 2003.

5 0
3 years ago
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