Answer:
x - 7
Step-by-step explanation:
x + 8 - 15
Subtract 15 - 8 = 7
x - 7
<u><em>~Lenvy~</em></u>
The picture is not on there. If you put the picture on there maybe I can help you.
Step-by-step explanation:
can u upload image?????? ;-;
The group of measures which would lead to the provided conclusion is the range is 7, the mean of the data is 12, the median is 12 and the mode is 11.
Given that, the data is around 12. If another measurement were taken, it would probably be around 12.
We need to find which group of measures would lead to this conclusion.
<h3>What are the mean, median and mode of the data set?</h3>
The mean of the data is the average value of the given data. The mean of the data is the ratio of the sum of all the values of data to the total number of values of data.
The median of the data is the middle value of the data set when it arrange in ascending or descending order. The data is around 12 which suggests that the median is 12.
Median=12
The mode of a data set is the value, which occurs most times for that data set. The value which has the highest frequency in the given set of data is known as the mode of that data set.
Mean and mode is around the median. For this case, the mean of the data is 12 and the mode is 11.
Mode=11
Mean=12
Thus, the group of measures which would lead to the provided conclusion is the range is 7, the mean of the data is 12, the median is 12 and the mode is 11.
Learn more about the mean, median and mode here;
brainly.com/question/14532771
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Answer:
a) nearest jump is JL = 1380 inches = 115ft
b) number of jumps in 1 mile N= 46 jumps
Step-by-step explanation:
Given that the jump length is proportional to the body length.
If 2 inch grasshopper can jump 40 inches.
JL = k(BL)
k = JL/BL
where JL = jump length = 40 inches
BL = Body length = 2 inches.
k = 40/2 = 20
The constant of proportionality is 20.
For the athlete :
BL = 5ft 9 inches = 5(12)+9 = 69 inches.
The jump length of the athlete is:
JL = k(BL) = 20(69)
JL = 1380 inches. = 115ft
The number of jumps in 1 mile is
1 mile = 63360 inches
N = 63360/1380
N = 45.9 = 46
N= 46
Therefore, 46 jumps would be needed.
