Answer:
n(B)=21.
Step-by-step explanation:
n(AUB) means the the number of elements in both A & B. And that includes the ones in common too.
n(A∩B) means the ones that in common.
n(A-B) refers to the elements that belong to A alone. That means the elements in A excluding the common elements.
n(B) is the number of elements that belong to B and that includes the common ones too.
Now coming to your question.
The total number of elements that can fit in both the sets is 36.
While the number of common elements is 16.
And also given that n(A-B)=15.
Now according to the definitions above....n(A) should include the ones that belong exclusively to A alone and also the ones in common.
So,
n(A)=n(A-B)+n(A∩B)
=15+16
=31
Therefore, n(A) is 31.
Now when n(AUB) is 36 and n(A) is 31, it is clear that the elements exclusive to B alone is 5, i.e.36-31.
Now n(B)=n(A∩B)+n(B-A)
Therefore, n(B) is 16+5 = 21.
n(B)=21.
Answer:
C)30%
Step-by-step explanation:
Prime numbers less than 30 are given below
2,3,5,7,11,13,17,19,23,29
We have to find the probability that sum of three prime numbers selected will be even.
We know that
Sum of any three prime number except 2 will be odd.
Total prime numbers except 2=9
Total prime numbers=10
Probability:P(E)=
Probability of getting sum of three prime numbers selected will be odd=
By using formula
Probability of getting sum of three prime numbers selected will be odd=P(E)=
Probability of getting sum of three prime numbers selected will be odd=P(E)=
Probability of getting sum of three prime numbers selected will be even=P(E')=1-0.7=0.3=
%
By using formula P(E')=1-P(E)
Answer:
use PEMDAS
Step-by-step explanation:
Parentheses
Exponents
Multiply
Divide
Add
Subtract.
if you do it in that exact order you should get your answer.
The interquartile range is affected by the existence of an outliner
8.45% = 0.0845
0.0845(25) = 2.1...ur answer is 25
