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3 years ago

I NEEEDDDD HELPPPP ASAPPPP ITS URGENTTTT!!!

Mathematics

1 answer:

vladimir2022 [97]3 years ago

5 0

Answer:

(x-13)^2+(y+16)^2=12.56

Step-by-step explanation:

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What is the solution of 6(3-2x)=54?

notka56 [123]

Hello!

You solve this algebraically

6(3 - 2x) = 54

distribute the 6

18 - 12x = 54

Subtract 18 from both sides

-12x = 36

Divide both sides by -12

x = -3

The answer is -3

Hope this helps!

3 0

3 years ago

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I need help fasttt

jenyasd209 [6]

B! Would be the answer! Good luck on the test!

5 0

4 years ago

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Mary baked 3 pies. 1 for her father, 1 for her friend joe, and 1 for her coworkers. Combination, permutaion or niether?

lbvjy [14]

The answer is permutation. It is the action of changing the arrangement, especially the linear order, of a set of items.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

6 0

3 years ago

A box contains 39 total coins and bills worth $36.60 all coins are either five dollar bills or nickels how many of each type are

Virty [35]

Answer:

7 $5 bills, 32 nickels

Step-by-step explanation:

Ok, so to solve this, we need to make two separate equations. If we say that x is the number of nickels, and y is the number of 5 dollar bills, adding up to $36.60, we can make the equations 0.05x + 5y = 36.60, and x + y = 39. Using substitution, we can say 0.05x + 5(39-x) = 36.60. This simplifies to 195-4.95x = 36.6. We can then say 158.4 = 4.95x, and x = 32. This means we have 32 nickels. As there are 39 total coins and bills, that means there are 7 $5 bills, and 32 nickels.

7 0

4 years ago

There were 800 math instructors at a mathematics convention. Forty instructors were randomly selected and given an IQ test. The

Leya [2.2K]

Answer:

95% confidence interval for the mean of the 800 instructors is [126.80 , 133.20].

Step-by-step explanation:

We are given that there were 800 math instructors at a mathematics convention.

Forty instructors were randomly selected and given an IQ test. The scores produced a mean of 130 with a standard deviation of 10.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean score = 130

s = sample standard deviation = 10

n = sample of instructors = 40

$\mu$ = population mean of 800 instructors

Here for constructing 95% confidence interval we have used One-sample t test statistics as we know don't about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.0225 < $t_3_9$ < 2.0225) = 0.95 {As the critical value of t at 39 degree of

freedom are -2.0225 & 2.0225 with P = 2.5%}

P(-2.0225 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.0225) = 0.95

P( $-2.0225 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.0225 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.0225 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.0225 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.0225 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.0225 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $130-2.0225 \times {\frac{10}{\sqrt{40} } }$ , $130+2.0225 \times {\frac{10}{\sqrt{40} } }$ ]

= [126.80 , 133.20]

Therefore, 95% confidence interval for the mean of the 800 instructors is [126.80 , 133.20].

5 0

3 years ago

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